有没有更干的方法来编写以下命令(将它们放入bash shell脚本中):
sudo sed -i 's/^#PermitRootLogin yes/PermitRootLogin no/' /etc/ssh/sshd_config
sudo sed -i 's/PermitRootLogin yes/PermitRootLogin no/' /etc/ssh/sshd_config
sudo sed -i 's/^#PermitEmptyPasswords yes/PermitEmptyPasswords no/' /etc/ssh/sshd_config
sudo sed -i 's/PermitEmptyPasswords yes/PermitEmptyPasswords no/' /etc/ssh/sshd_config
sudo sed -i 's/^#PasswordAuthentication yes/PasswordAuthentication no/' /etc/ssh/sshd_config
sudo sed -i 's/PasswordAuthentication yes/PasswordAuthentication no/' /etc/ssh/sshd_config
sudo sed -i 's/^#X11Forwarding yes/X11Forwarding no/' /etc/ssh/sshd_config
sudo sed -i 's/X11Forwarding yes/X11Forwarding no/' /etc/ssh/sshd_config
最佳答案
由于要匹配的模式是相似的,因此您可以对4个字符串进行交替使用并捕获它。将字符串开头的#
设为可选。
以下内容将它们合并为一个:
sed -i -r 's/^#?(PermitRootLogin|PermitEmptyPasswords|PasswordAuthentication|X11Forwarding) yes/\1 no/' /etc/ssh/sshd_config
如果您的
sed
版本不支持扩展的正则表达式,则可以说:sed -i 's/^#\{0,1\}\(PermitRootLogin\|PermitEmptyPasswords\|PasswordAuthentication\|X11Forwarding\) yes/\1 no/' /etc/ssh/sshd_config