我已经建立了一个客户Oracle AQ。我在CLIENT_ACKNOWLEDGE
模式的Java Web应用程序中观察到来自此队列的消息。但是,一旦我收到onMessage
方法中的消息,这些消息似乎就会从Oracle队列中删除。我的假设是,除非我在客户端中acknowledge
消息,否则不应删除该消息。如何停止呢?
Oracle Queue模式如下所示:
BEGIN DBMS_AQADM.CREATE_QUEUE_TABLE(
Queue_table => '"TESTUSER"."myqueuetable"',
Queue_payload_type => 'TESTUSER.messageobject',
multiple_consumers => false
);
END;
/
BEGIN DBMS_AQADM.CREATE_QUEUE(
Queue_name => 'TESTUSER.myqueue',
Queue_table => 'TESTUSER.myqueuetable',
Queue_type => 0, Max_retries => 5, Retry_delay => 0
);
END;
/
BEGIN dbms_aqadm.start_queue (
queue_name => 'testuser.myqueue'
);
END;
我这样观察我的Java应用程序中的消息
//somewhere in my app
session = queueConnection.createQueueSession(false, Session.CLIENT_ACKNOWLEDGE);
queueReceiver = ((AQjmsSession) databaseConnectionManager.getSession())
.createReceiver(databaseConnectionManager.getQueue(), Messageobject.getORADataFactory());
queueReceiver.setMessageListener(this);
//in my listener class
@Override
public void onMessage(Message message) {
AdtMessage msg = (AdtMessage) message;
try {
Messageobject message = (Messageobject) msg.getAdtPayload();
if (isUserConnected(message.userId)) {
logger.debug("Message acknowledged");
msg.acknowledge();
//handle the message. the message should be deleted now.
} else {
//i don't want the message to be deleted
}
} catch (JMSException | IllegalArgumentException | SQLException e) {
logger.error("An error occurred while sending an outgoing blob", e);
}
}
最佳答案
您正在创建一个使用者队列,该消息在成功使用后将立即删除。
要保留消息,请在创建队列时将tention_time设置为大于零的值。
BEGIN
DBMS_AQADM.CREATE_QUEUE(
Queue_name => 'TESTUSER.myqueue',
Queue_table => 'TESTUSER.myqueuetable',
Queue_type => 0, Max_retries => 5, Retry_delay => 0,
retention_time => 300 -- retain for next 5 minutes
);
END;
/
请参阅https://docs.oracle.com/database/121/ARPLS/d_aqadm.htm#ARPLS109