我正在使用c++通过SSH Secure Shell在Solaris机器上远程测试代码。不确定什么版本; Solaris,c++ / compiler等(并且不知道如何通过SSH Secure Shell进行查找)...
这段代码:
#include <iostream>
#include <string>
#include <cstdlib>
#include <errno.h>
using std::cout;
using std::cin;
using std::string;
enum STR_TO_INT_STATUS { SUCCESS, OVERFLOW, UNDERFLOW, INCONVERTIBLE };
STR_TO_INT_STATUS str_to_int( int&, char const*, int );
int main()
{
int num;
string str;
STR_TO_INT_STATUS code;
cout << "\nEnter a string containing numbers: ";
cin >> str;
code = str_to_int( num, str.c_str(), 0 );
if( code == OVERFLOW || code == UNDERFLOW )
cout << "\nThe number was out of int's range\n\n";
else if( code == INCONVERTIBLE )
cout << "\nThe string contained non-number characters\n\n";
else if( code == SUCCESS )
cout << "\nThe int version of the string is: " << num << "\n\n";
}
STR_TO_INT_STATUS str_to_int( int &i, char const* s, int base )
{
char *end;
long l;
errno = 0;
l = strtol( s, &end, base );
if( ( errno == ERANGE && l == LONG_MAX ) || l > INT_MAX )
return OVERFLOW;
if( ( errno == ERANGE && l == LONG_MIN ) || l < INT_MIN )
return UNDERFLOW;
if( *s == '\0' || *end != '\0' )
return INCONVERTIBLE;
i = l;
return SUCCESS;
}
编译并可以正常工作...如您所见,它将用户输入的字符串转换为整数。
但是当这样修改时:
#include <iostream>
#include <string>
#include <cstdlib>
#include <errno.h>
#include <limits>
#include <cmath>
using std::cout;
using std::cin;
using std::string;
using std::numeric_limits;
int size_of( int ); //------------------------------------------------- :62
enum STR_TO_INT_STATUS { SUCCESS, OVERFLOW, UNDERFLOW, INCONVERTIBLE };
STR_TO_INT_STATUS str_to_int( int&, char const*, int ); //------------- :84
int main()
{
int num;
string str;
string dummy;
STR_TO_INT_STATUS code;
system( "clear" );
cout << "\nint's max limit: "
<< numeric_limits<int>::max()
<< "\nint's min limit: "
<< numeric_limits<int>::min()
<< "\n\nnumber of digits in the largest int: "
<< size_of( numeric_limits<int>::max() )
<< "\nnumber of digits in the smallest int: "
<< size_of( numeric_limits<int>::min() );
cout << "\nEnter a string containing numbers: ";
cin >> str;
code = str_to_int( num, str.c_str(), 0 );
if( code == OVERFLOW || code == UNDERFLOW )
cout << "\nThe number was out of int's range\n\n";
else if( code == INCONVERTIBLE )
cout << "\nThe string contained non-number characters\n\n";
else if( code == SUCCESS )
cout << "\nThe int version of the string is: " << num << "\n\n";
cout << "Press enter key to continue...";
getline( cin, dummy );
system( "clear" );
return( 0 );
}
int size_of( int num )
{
int length = 0;
num = ( int )fabs( num );
if( num == 0 )
length = 1;
else
while( num > 0 )
{
length++;
num /= 10;
}
return( length );
}
STR_TO_INT_STATUS str_to_int( int &i, char const* s, int base )
{
char *end;
long l;
errno = 0;
l = strtol( s, &end, base );
if( ( errno == ERANGE && l == LONG_MAX ) || l > INT_MAX )
return OVERFLOW;
if( ( errno == ERANGE && l == LONG_MIN ) || l < INT_MIN )
return UNDERFLOW;
if( *s == '\0' || *end != '\0' )
return INCONVERTIBLE;
i = l;
return SUCCESS;
}
我收到以下编译错误:
int_limits.cpp:16: error: expected identifier before numeric constant
int_limits.cpp:16: error: expected `}' before numeric constant
int_limits.cpp:16: error: expected unqualified-id before numeric constant
int_limits.cpp:16: error: expected `,' or `;' before numeric constant
int_limits.cpp:16: error: expected declaration before '}' token
我一直在寻找拼写错误,试图移动枚举行的位置...我不知道这是怎么回事。
对此问题的任何帮助将不胜感激!
最佳答案
cmath
的包含内容将预处理程序常量OVERFLOW
定义为3,并将UNDERFLOW
定义为4。因此,声明枚举的行变为(如果没有其他常量):
enum STR_TO_INT_STATUS { SUCCESS, 3, 4, INCONVERTIBLE };
当然,这是无效的语法。
关于c++ - 我遇到有关枚举的错误(我认为),我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/31245596/