请考虑以下HTML:

<div class="week start-available start-mid end-available end-mid overlap-False">


                <a href="http://alink.com" class="20130906-20130912">
                    <span class="wk-start" style="">

                            <span class="day overlap-False">9 </span>


                            <span class="day overlap-False">10 </span>


                            <span class="day overlap-False">11 </span>


                            <span class="day overlap-False">12 </span>

                    </span>
                </a>



                <a href="http://alink.com" class="20130913-20130919">
                    <span class="wk-end">

                            <span class="day overlap-False">13 </span>


                            <span class="day overlap-False">14 </span>


                            <span class="day overlap-False">15 </span>

                    </span>
                </a>


            </div>
<div class="week start-available start-mid end-available end-mid overlap-False">


                <a href="http://alink.com" class="20130913-20130919">
                    <span class="wk-start" style="">

                            <span class="day overlap-False">16 </span>


                            <span class="day overlap-False">17 </span>


                            <span class="day overlap-False">18 </span>


                            <span class="day overlap-False">19 </span>

                    </span>
                </a>



                <a href="http://alink.com" class="20130920-20130926">
                    <span class="wk-end">

                            <span class="day overlap-False">20 </span>


                            <span class="day overlap-False">21 </span>


                            <span class="day overlap-False">22 </span>

                    </span>
                </a>


            </div>


我想使用jquery将css应用于与当前徘徊的锚相同类的锚。每个锚都有另一个相同的类,但属于不同的父级。

我假设我需要遍历所有元素以匹配所徘徊的元素的类,但必须承认我有点迷茫。任何帮助将不胜感激。

最佳答案

尝试

var $as = $('.week > a').hover(function(){
    $as.not(this).filter('.' + this.className).addClass('test')
}, function(){
    $as.not(this).filter('.' + this.className).removeClass('test')
})


演示:Fiddle

10-04 22:06
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