我正在使用以下代码获取iPhone联系人,但我的应用未在iOS 9中获得允许联系人的权限。我从堆栈中找到了此代码,其他引用也相同。
- (void)getPersonOutOfAddressBook
{
//1
CFErrorRef error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
if (addressBook != nil) {
NSLog(@"Succesful.");
//2
NSArray *allContacts = (__bridge_transfer NSArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
//3
NSUInteger i = 0; for (i = 0; i < [allContacts count]; i++)
{
NSMutableDictionary *persiondict =[[NSMutableDictionary alloc]init] ;
// Person *person = [[Person alloc] init];
ABRecordRef contactPerson = (__bridge ABRecordRef)allContacts[i];
//4
NSString *firstName = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson,
kABPersonFirstNameProperty);
NSString *lastName = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson, kABPersonLastNameProperty);
NSString *fullName = [NSString stringWithFormat:@"%@ %@", firstName, lastName];
// person.firstName = firstName;
// person.lastName = lastName;
// person.fullName = fullName;
[persiondict setValue:fullName forKey:@"fullName"] ;
//email
//5
ABMultiValueRef emails = ABRecordCopyValue(contactPerson, kABPersonEmailProperty);
//6
NSUInteger j = 0;
for (j = 0; j < ABMultiValueGetCount(emails); j++) {
NSString *email = (__bridge_transfer NSString *)ABMultiValueCopyValueAtIndex(emails, j);
if (j == 0) {
// person.homeEmail = email;
[persiondict setValue:email forKey:@"email"] ;
// NSLog(@"person.homeEmail = %@ ", person.homeEmail);
}
else if (j==1)
[persiondict setValue:email forKey:@"email"] ;
}
//7
[ArrUserOfContacts addObject:persiondict];
}
//8
CFRelease(addressBook);
} else {
//9
NSLog(@"Error reading Address Book");
}
}
我在这里找不到问题,用户如何获得访问联系人的权限。任何建议都会有所帮助。
最佳答案
您需要使用ABAddressBookRequestAccessWithCompletion()
的请求权限
ABAddressBookRequestAccessWithCompletion(ABAddressBookCreateWithOptions(NULL, nil), ^(bool granted, CFErrorRef error) {
if (!granted){
NSLog(@"Just denied");
return;
}
NSLog(@"Just authorized");
});
关于ios - 应用程序未要求联系人权限以访问iOS 9中的联系人,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/37615482/