更新:我不同意这是重复的-因为我正在寻找退出主应用程序并仍然从该服务显示Toast的方法。

a very simple test app中,我有2个按钮:

点击任意按钮将运行带有相应操作字符串(“打开”或“闪光”)的服务-

OpenActivity.java:

public class OpenActivity extends Activity {
    private Intent mServiceIntent;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_open);
        mServiceIntent = new Intent(this, RegionService.class);
   }

    public void openCar(View v) {
        mServiceIntent.setAction("open");
        startService(mServiceIntent);
    }

RegionService.java:
public class RegionService extends IntentService {
    private static final String TAG = "RegionService";

    @Override
    protected void onHandleIntent(Intent intent) {
        Log.d(TAG, "Received an intent: " + intent);
        String action = intent.getAction();
        Log.d(TAG, "Received an action: " + action);

        if(action.equals("open")) {
            Toast.makeText(this,
                    getString(R.string.car_opened),
                    Toast.LENGTH_SHORT).show();
        }

不幸的是,我的应用崩溃了:
D/RegionService(24506): Received an intent: Intent { act=open cmp=de.afarber.mynotification/.RegionService }

D/RegionService(24506): Received an action: open

W/MessageQueue(24506): Handler (android.os.Handler) {422768a8} sending message to a Handler on a dead thread
W/MessageQueue(24506): java.lang.RuntimeException: Handler (android.os.Handler) {422768a8} sending message to a Handler on a dead thread
W/MessageQueue(24506):  at android.os.MessageQueue.enqueueMessage(MessageQueue.java:320)
W/MessageQueue(24506):  at android.os.Handler.enqueueMessage(Handler.java:626)
W/MessageQueue(24506):  at android.os.Handler.sendMessageAtTime(Handler.java:595)
W/MessageQueue(24506):  at android.os.Handler.sendMessageDelayed(Handler.java:566)
W/MessageQueue(24506):  at android.os.Handler.post(Handler.java:326)
W/MessageQueue(24506):  at android.widget.Toast$TN.hide(Toast.java:370)
W/MessageQueue(24506):  at android.app.ITransientNotification$Stub.onTransact(ITransientNotification.java:54)
W/MessageQueue(24506):  at android.os.Binder.execTransact(Binder.java:412)
W/MessageQueue(24506):  at dalvik.system.NativeStart.run(Native Method)

作为一名Android编程新手,我想知道如何以正确的方式从Service中显示Toast

我想我已经在Android Home上看到Toasts(即设备屏幕上没有“ Activity ”,但仍然有Toasts)。

我的背景:我想通过我的服务监视信标设备,并显示一些Toasts文本-即使我的应用程序已关闭。

最佳答案

OnHandleIntent将以不同的Thread运行
所以你在android中不允许的线程中显示Toast
所以像这样改变你的代码

Handler handler = new Handler(Looper.getMainLooper());
handler.post(new Runnable() {

    @Override
    public void run() {
         Toast.makeText(getApplicationContext(),
                       getString(R.string.car_opened),
                       Toast.LENGTH_SHORT).show();
    }
});

从这个dead thread in service

IntentService将创建一个线程来处理新的意图,并在任务完成后立即终止它。因此,Toast将不受死线程的控制。

屏幕上显示吐司时,您应该在控制台中看到一些异常(exception)情况。

10-07 20:00
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