Python 新手 - 石头、纸、剪刀

我对 Python 非常陌生，并决定给自己设定一个挑战，即在不复制其他人的代码的情况下编写石头剪刀布游戏。但是，我需要 Pythonista 大人的帮助!

我在这里看到了许多其他关于 Rock, Paper, Scissors 的变体，但没有解释为什么我的版本不起作用。我的程序基本上遵循这种格式:在开始时设置空变量，定义 4 个打印介绍文本的函数，接收玩家输入，随机选择计算机的选择，然后评估玩家是赢还是输。

这一切都被困在一个 while 循环中，一旦玩家选择他们不想再玩，这个循环就会中断。 (这一点工作正常)

但是，每当我运行代码时，它总是会进行绘制，并且似乎没有为计算机的选择函数调用存储任何数据。有谁知道我做错了什么？

非常感谢!

import random

playerAnswer = ''
computerAnswer = ''
winsTotal = 0
timesPlayed = 0

def showIntroText():
    print('Time to play Rock, Paper, Scissors.')
    print('Type in your choice below:')

def playerChoose():
    playerInput = input()
    return

def computerChoose():
    randomNumber = random.randint(1, 3)
    if randomNumber == 1:
        computerPick = 'Paper'
    elif randomNumber == 2:
        computerPick = 'Scissors'
    else:
        computerPick = 'Rock'
    return

def assessResult():
    if playerAnswer == computerAnswer:
        print('Draw!')
    elif playerAnswer == 'Rock' and computerAnswer == 'Paper':
        print('Paper beats Rock. You lose!')
    elif playerAnswer == 'Paper' and computerAnswer == 'Scissors':
        print('Scissors cuts Paper. You lose!')
    elif playerAnswer == 'Scissors' and computerAnswer == 'Rock':
        print('Rock blunts Scissors. You lose!')
    else:
        print('You win!')
        winsTotal += 1
    return

while True:
    timesPlayed += 1

    showIntroText()

    playerAnswer = playerChoose()
    computerAnswer = computerChoose()

    assessResult()

    print('Do you want to play again? (y/n)')
    playAgain = input()
    if playAgain == 'n':
        break

print('Thank you for playing! You played ' + str(timesPlayed) + ' games.')

最佳答案

在大多数情况下，您都错过了返回值。

** 在 playerChoose() 中添加 ' return playerInput ' 而不是只返回。

** 在 computerChoose() 中添加 ' return computerPick ' 而不是 return。

** 在将 winsTotal 变量用作 'winsTotal = 0 ' 之前初始化 评估结果() 变量。

** 您在程序开始时初始化的变量超出了函数的范围。

请检查此 StackOverFlow link 以了解 变量在 python 中的范围。

** 在 评估结果() 中添加 ' return winsTotal ' 而不是 return。

import random

def showIntroText():
    print('Time to play Rock, Paper, Scissors.')
    print('Type in your choice below:')

def playerChoose():
    playerInput = input()
    return playerInput

def computerChoose():
    randomNumber = random.randint(1, 3)
    if randomNumber == 1:
        computerPick = 'Paper'
    elif randomNumber == 2:
        computerPick = 'Scissors'
    else:
        computerPick = 'Rock'
    return computerPick

def assessResult(winsTotal):
    if playerAnswer == computerAnswer:
        print('Draw!')
    elif playerAnswer == 'Rock' and computerAnswer == 'Paper':
        print('Paper beats Rock. You lose!')
    elif playerAnswer == 'Paper' and computerAnswer == 'Scissors':
        print('Scissors cuts Paper. You lose!')
    elif playerAnswer == 'Scissors' and computerAnswer == 'Rock':
        print('Rock blunts Scissors. You lose!')
    else:
        print('You win!')
        winsTotal += 1
    return winsTotal


total_win = 0
while True:

    timesPlayed += 1

    showIntroText()

    playerAnswer = playerChoose()
    computerAnswer = computerChoose()

    total_win = assessResult(total_win)

    print('Do you want to play again? (y/n)')
    playAgain = input()
    if playAgain == 'n':
        break

print('Thank you for playing! You played ' + str(timesPlayed) + ' games.' + 'Out of which you won '+ str(total_win))

输出:

   C:\Users\dinesh_pundkar\Desktop>python c.py
Time to play Rock, Paper, Scissors.
Type in your choice below:
"Rock"
You win!
Do you want to play again? (y/n)
"y"
Time to play Rock, Paper, Scissors.
Type in your choice below:
"Rock"
Draw!
Do you want to play again? (y/n)
"y"
Time to play Rock, Paper, Scissors.
Type in your choice below:
"Rock"
Paper beats Rock. You lose!
Do you want to play again? (y/n)
"y"
Time to play Rock, Paper, Scissors.
Type in your choice below:
"Rock"
Paper beats Rock. You lose!
Do you want to play again? (y/n)
"n"
Thank you for playing! You played 4 games.Out of which you won 1

关于Python 新手 - 石头、纸、剪刀，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/39467619/