我完成了工作-但我的输出很奇怪。我基本上是在尝试比较一堆对象,如果它们共享ttns并且时间用完了-那么它们需要重新计算其ttns。检查所有主机后,我增加时钟并重试。目的是找到可以通过检查而不会碰撞的拳头主机。这基本上是对网络的模拟,如果两个主机同时发送(时钟),则该网络会进行一些补偿计算。我进行了检查,以确保主机未对自身进行检查-我知道我的预期输出是,不是。我已经完成了几次,但是找不到逻辑错误。有指针吗?

// Should insert n number as argument 1 on the command line.
#include <iostream>
#include <vector>
#include <stdlib.h> // srand(), time()

static int CLOCK = 0;

class Host{
  private:
    int sid;
    int cc;
    int ttns;

  public:
    Host();
    int get_sid(){ return sid; }
    void set_sid(int id){ sid = id; }
    int get_cc(){ return cc; }
    void inc_cc(){ cc += 1; }
    int get_ttns(){ return ttns; }
    void new_ttns(){ ttns = (rand()%(cc+1))+CLOCK+1; }
  };

Host::Host(){
  sid  = -666;
  cc   = 0;
  ttns = 0;
}

bool work(std::vector<Host> &hosts){
  int count = 0;

  for(CLOCK = 0; /*INFINITE*/; CLOCK++){
      for(int i = 0; i < hosts.size(); i++){
        count = 0;
          for(int n = 0; n < hosts.size(); n++){
              if( (i != n) && /* host i doesn't compare to host n */
                  (hosts[i].get_ttns() == hosts[n].get_ttns()) &&/* host i and n share ttns */
                  (hosts[i].get_ttns() == CLOCK)  /* host i ttns = now */
                ){
                hosts[i].inc_cc();
                hosts[i].new_ttns();
                count = -666; // collision occured
              }
          count++;
          }
        if ( count == hosts.size() ){
          std::cout << "Host " << hosts[i].get_sid() << "\nTTNS: " << hosts[i].get_ttns();
          std::cout << std::endl;
          return false;
        }
     }
  }

  return true; // pretty pointless
}

int main(int argc, char *argv[]){
  srand(time(NULL));
  std::vector<Host> hosts;

  // Push hosts into vector
  int nhosts = atoi(argv[1]);
  for(int i = 0; i < nhosts; i++){
    Host newhost;
    newhost.set_sid(i);
    hosts.push_back(newhost);
  }

  while (work(hosts)){
    ; // hang out
  }

  return 0;
}

最佳答案

错误之一可能在此行中:

(hosts[i].get_ttns() == CLOCK)

您无法比较这点,因为CLOCK是全局的,并且增加了一个以上的主机。这意味着主机没有单调的时钟。

也许你想要这个:
(hosts[i].get_ttns() <= CLOCK

关于c++ - 我的逻辑在哪里失败?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/5562654/

10-11 22:35
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