正如标题所示,我的目标是能够从 script.gs
发送推文。该推文将发布到我的提要中,理想情况下我不必访问 Twitter 网站。
我写了两个主要函数来尝试这个:
脚本文件
//post tweet
function oAuth() {
var CONSUMER_KEY = "**********************";
var CONSUMER_SECRET = "*************************************************";
ScriptProperties.setProperty("TWITTER_CONSUMER_KEY", CONSUMER_KEY);
ScriptProperties.setProperty("TWITTER_CONSUMER_SECRET", CONSUMER_SECRET);
var oauthConfig = UrlFetchApp.addOAuthService("twitter");
oauthConfig.setAccessTokenUrl("https://api.twitter.com/oauth/access_token");
oauthConfig.setRequestTokenUrl("https://api.twitter.com/oauth/request_token");
oauthConfig.setAuthorizationUrl("https://api.twitter.com/oauth/authorize");
oauthConfig.setConsumerKey(ScriptProperties.getProperty("TWITTER_CONSUMER_KEY"));
oauthConfig.setConsumerSecret(ScriptProperties.getProperty("TWITTER_CONSUMER_SECRET"));
var options = {muteHttpExceptions: true,oAuthServiceName:'twitter',oAuthUseToken:'always'}
var url = "https://api.twitter.com/1.1/statuses/user_timeline.json";
var response = UrlFetchApp.fetch(url, options).getContentText();
Logger.log(response);
}
function postTweet() {
oAuth();
Logger.log('oAuth complete');
var status = "Tweet";
var Roptions = {
method: "post",
oAuthServiceName: "twitter",
oAuthUseToken: "always",
status: status
};
var url = "https://api.twitter.com/1.1/statuses/update.json";
Logger.log('begin post');
var request = UrlFetchApp.fetch(url, Roptions); //the trouble line. Execution stops.
Logger.log('post complete');
}
经过大约一天无情的黑客攻击,我能够使第一个函数
oAuth()
工作。那记录了我的用户数据。但是,对于我的一生,我无法弄清楚是什么阻碍了 request
。我确实收到此错误: Request failed for returned code 403. Truncated server response: {"errors":[{"message":"SSL is required","code":92}]}
。谷歌搜索这并没有出现太多。我猜这个问题出在 Roptions
的某个地方。任何帮助将不胜感激,如果需要,我可以尝试提供进一步的说明。 最佳答案
Eureka !这是解决方案。具有讽刺意味的是,我以前也有过这样的事情,但已经驳回了。原来 https
是我最大的问题。今晚我将享用不起眼的馅饼。
发送推文的脚本
//post tweet
function oAuth() {
var CONSUMER_KEY = "*************************";
var CONSUMER_SECRET = "**************************************************";
ScriptProperties.setProperty("TWITTER_CONSUMER_KEY", CONSUMER_KEY);
ScriptProperties.setProperty("TWITTER_CONSUMER_SECRET", CONSUMER_SECRET);
var oauthConfig = UrlFetchApp.addOAuthService("twitter");
oauthConfig.setAccessTokenUrl("https://api.twitter.com/oauth/access_token");
oauthConfig.setRequestTokenUrl("https://api.twitter.com/oauth/request_token");
oauthConfig.setAuthorizationUrl("https://api.twitter.com/oauth/authenticate");
oauthConfig.setConsumerKey(ScriptProperties.getProperty("TWITTER_CONSUMER_KEY"));
oauthConfig.setConsumerSecret(ScriptProperties.getProperty("TWITTER_CONSUMER_SECRET"));
var options = {muteHttpExceptions: true,oAuthServiceName:'twitter',oAuthUseToken:'always'}
var url = "https://api.twitter.com/1.1/statuses/user_timeline.json";
var response = UrlFetchApp.fetch(url, options).getContentText();
Logger.log(response);
}
function postTweet() {
oAuth();
Logger.log('oAuth complete');
var status='Test tweet';
var options = {
"method": "post",
"oAuthServiceName": "twitter",
"oAuthUseToken": "always",
"payload":{"status":status}
};
var url = "https://api.twitter.com/1.1/statuses/update.json";
Logger.log('begin post');
var request = UrlFetchApp.fetch(url, options);
Logger.log('post complete');
}
当您注册 Twitter 应用程序时,您必须检查选项
Allow this application to be used to Sign in with Twitter
。这可以防止持续的授权弹出窗口。此外,推文文本不能包含单引号( '
)。关于twitter - 使用 Google Apps 脚本向我的提要发布推文,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/25577921/