$(document).ready(function(){
$("#promptButton").click(function(){
$("#openPrompt").hide();
startGame();
});
});
function startGame(){
$(document).ready(function(){
$("#gameboard").append("<div class='snakeHead' id='head'> hi </div>");
var direction;
moveTimer = setInterval(function() {snakeMove()},1000);
function snakeMove(){
function snakeDirection(){
$(".snakeHead").keydown(function(key){
if (key.which === 38){
direction = "up";
return {"margin-top": "-=20px"}
} else if(key.which === 40){
direction = "down"
return {"margin-top": "+=20px"}
} else if(key.which === 37){
direction = "left"
return {"margin-left": "-=20px"}
} else if(key.which === 39){
direction = "right"
return {"margin-left": "+=20px"}
} else {
direction = "right"
return {"margin-left": "+=20px}"
};
});
};
$('.snakeHead').animate({'margin-left':'+=20px'}, 'slow');
}
});
};
我不断
SyntaxError:期望的表达式,在第32行第11行上显示')'。
我的印象是
keydown()
仅需要使用事件触发时要调用的函数来调用。我需要另一个表达式来调用吗?感谢您的帮助,这是我正在尝试的第一个实际项目,并且我是自学成才的,因此请尝试对我来说尽可能清晰。谢谢!
最佳答案
您有语法错误:
function startGame(){
$(document).ready(function(){
$("#gameboard").append("<div class='snakeHead' id='head'> hi </div>");
var direction;
moveTimer = setInterval(function() {snakeMove()},1000);
function snakeMove(){
function snakeDirection(){
$(".snakeHead").keydown(function(key){
if (key.which === 38){
direction = "up";
return {"margin-top": "-=20px"}
} else if(key.which === 40){
direction = "down"
return {"margin-top": "+=20px"}
} else if(key.which === 37){
direction = "left"
return {"margin-left": "-=20px"}
} else if(key.which === 39){
direction = "right"
return {"margin-left": "+=20px"}
} else {
direction = "right"
return {"margin-left": "+=20px}" <--- Here --->
};
});
};
$('.snakeHead').animate({'margin-left':'+=20px'}, 'slow');
}
});
};