您好,我无法完成这项工作,如果在主词中包含该词,则给我一个主词,然后再提供另一个子词,应删除该部分。

//Example
//fmrog (in.nextLine)(main word)
//4  (in.nextInt)(the amount of sub words)
//roc(in.nextLine)(not contained)
//gor(in.nextLine)(not contained)
//rog(in.nextLine)(contained)
//ogr(in.nextLine)(not contained)
//result:fm
  public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    StringBuilder mainWord = new StringBuilder(in.nextLine);
    int n = in.nextInt();
    StringBuilder MainWord2 = new StringBuilder(mainWord);
    in.nextLine();
    for (int i = 0; i < n; i++) {
        String subWord = in.nextLine();
        int chars = subWord.length();
        if (chars> mainWord.length()){
            continue;
        }
        for (int j = 0; j < subWord.length(); j++) {
            int r = 0;

            for (int k = 0; k < mainWord.length(); k++) {
                r++;
                if (k > MainWord2.length() - 1) {
                    break;
                }
                if (MainWord2.charAt(k) == subWord.charAt(j)) {
                    break;
                }
            }
            if (r <= MainWord2.length() && MainWord2.charAt(r-1) == subWord.charAt(j)) {
                MainWord2.deleteCharAt(r - 1);
                if (j >= subWord.length() -1 ) {
                    mainWord = MainWord2;
                    break;
                }
            }
            if (r > MainWord2.length()) {
                MainWord2 = mainWord;
                break;
            }

        }
    }
        System.out.println(mainWord);
    }
}


老实说,我可能会遇到一种更简单的方法来解决此问题。最主要的是,当我编写类似“ Super 2 pe surr”的案例时,在“ surr”末尾,当我删除chatAt时,两个StringBuilder开始充当一个。

最佳答案

无需使其变得如此复杂。

String input = // complete user input
String[] words = String.split(input);
String mainWord = words[0];
int numWords = Integer.parseInt(words[1]); // this variable isn't needed

for(int i = 2; i < words.length; i++) {
  if (mainWord contains words[i]) {
    mainWord = mainWord.replace(words[i], ""); // remove subword from mainword
  }
}


最后,mainWord将是原始的mainWord,不包含以后输入的任何子词。

关于java - Java从单词中删除部分,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/49702701/

10-08 22:32
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