java - 如何在Android中进行搜索

我有以下代码可以正常工作。.我想添加搜索功能...您能告诉我该怎么做以及在哪里

MyDatabase.java

package com.example.test4;

import android.content.ContentValues;
import android.content.Context;
import android.database.Cursor;
import android.database.SQLException;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteDatabase.CursorFactory;
import android.database.sqlite.SQLiteOpenHelper;
import android.util.Log;

public class MyDatabase {
    public static final String MY_DB2 = "testdb5";
    MyHelper mh;
    Context myCon;
    SQLiteDatabase sdb;

    public MyDatabase(Context c) {
        myCon = c;
        mh = new MyHelper(myCon, MY_DB2, null, 1);
    }

    public void open() {
        sdb = mh.getWritableDatabase();
    }

    public class MyHelper extends SQLiteOpenHelper {

        public MyHelper(Context context, String name, CursorFactory factory,
                int version) {
            super(context, name, factory, version);
            // TODO Auto-generated constructor stub
        }

        @Override
        public void onCreate(SQLiteDatabase db) {
            db.execSQL("create table students(_id integer primary key, "
                    + "s_name text, " + "s_attendance text, "
                    + "s_homework text, " + "s_participation text, "
                    + "s_quiz integer, " + "s_test integer, "
                    + "s_comment text, " + "p_email text);");
            Log.d("1", "Table Created");
        }

        @Override
        public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
            // TODO Auto-generated method stub

        }

    }

    public void StudentsInsert(ContentValues cv) {
        sdb.insert("students", null, cv);
    }

    public Cursor getStudents() {
        Cursor c = sdb.query("students", null, null, null, null, null, null);
        return c;
    }

    public Cursor filterStudents() {
        // SQLiteDatabase db = mh.getReadableDatabase();

        Cursor c = sdb.query("students", new String[] { "s_name",
                "s_attendance", "s_homework", "s_participation", "s_quiz",
                "s_test", "s_comment", "p_email" }, "s_name like %a%", null,
                null, null, null);
        return c;

    }

}

我认为我在filterStudents（）中做错了...

这是我在其他文件上所拥有的

EditText myFilter = (EditText) findViewById(R.id.myFilter);
        myFilter.addTextChangedListener(new TextWatcher() {

         public void afterTextChanged(Editable s) {
         }

         public void beforeTextChanged(CharSequence s, int start,
           int count, int after) {
         }

         public void onTextChanged(CharSequence s, int start,
           int before, int count) {
          sca.getFilter().filter(s.toString());
         }
        });

        sca.setFilterQueryProvider(new FilterQueryProvider() {
               public Cursor runQuery(CharSequence constraint) {
                   return mdb.filterStudents();
               }
           });

最佳答案

尝试在过滤器字符串周围加上引号。即，代替：

like %a%

做了：

like '%a%'

保持双引号（“）不变，但在过滤器字符串周围添加单引号。