我将这个String解析为一个Javascript对象。

{
"startTime": 233432420233,
"endTime": 233432431000,
"bufferingDelays": [
    {
        "time": 233432420233,
        "delayLength": 100
    },
    {
        "time": 233432420433,
        "delayLength": 50
    },
    {
        "time": 233432420833,
        "delayLength": 75
    }
    ]
}

这是Javascript代码进行解析,然后转换为JSON字符串:
var reportObject = jQuery.parseJSON(reportJSONString);

reportObject.startTime = new Date(reportObject.startTime);
reportObject.endTime = new Date(reportObject.endTime);

for (var i = 0; i < reportObject.bufferingDelays.length; i++)
{
    var delay = reportObject.bufferingDelays[i];
    delay.time = new Date( delay.time );

    reportObject.bufferingDelays[i] = delay;
}

var reportObjectFinalString = JSON.stringify( reportObject );

JSON转换产生的日期之一是:1977-05-25T18:20:20.233Z。我认为尾随的“Z”不好。

现在,在Java中,我尝试将其解析为Java对象,如下所示:
Gson gson = new GsonBuilder().setDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ").create();
Report report = gson.fromJson( jsonBuilder.toString(), Report.class );

但是我得到了这个异常(exception):
SEVERE: Servlet.service() for servlet [ReportServlet] in context with path [/Report] threw exception [com.google.gson.JsonSyntaxException: 1977-05-25T18:20:20.233Z] with root cause
java.text.ParseException: Unparseable date: "1977-05-25T18:20:20.233Z"

最佳答案

您还需要引用Z

Gson gson = new GsonBuilder().setDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").create();

SimpleDateFormat (在GsonBuilder中使用)采用未加引号的Z表示您的日期字符串没有的时区。

10-07 13:17
查看更多