我有点棘手，无法找到好的解决方案。
我有以下类型的数组：
data = [ '1', '1', '964', '718', '0', '0', '0' ];
如下：
数据[0] =幻灯片编号
数据[1] =形状编号
数据[2] =宽度
数据[3] =高度
数据[4] =左
数据[5] =顶部
数据[6] = href
说明
一张幻灯片可以有多个形状，每个形状都有5个属性（宽度，高度，左侧，顶部，href）。
目标
我想创建一个可以容纳所有数据的大对象。
像这样：
[{"Slide1" : [{
"Shape1" : {
"Width" : 200,
"Height" : 100,
"Left" : 200,
"Top" : 100,
"Link" : "1"
}
}, {
"Shape2" : {
"Width" : 200,
"Height" : 100,
"Left" : 200,
"Top" : 100,
"Link" : "0"
}
}]
}, {
"Slide2" : [{
"Shape1" : {
"Width" : 200,
"Height" : 100,
"Left" : 200,
"Top" : 100,
"Link" : "0"
}
}, {
"Shape2" : {
"Width" : 200,
"Height" : 100,
"Left" : 200,
"Top" : 100,
"Link" : "1"
}
}, {
"Shape3" : {
"Width" : 200,
"Height" : 100,
"Left" : 200,
"Top" : 100,
"Link" : "2"
}
}]
}]
我编写了以下代码，几乎可以将我带到那里，但仍然没有结束：
for(var x = 0; x<data.length; x++){
data[x] = data[x].slice(1, -1);
data[x] = data[x].split("#");
}
var count = 0;
var total_slides = 66;
var slidesnr_and_shapesnr = {};
var data_object = {};
while(count < data.length)
{
slidesnr_and_shapesnr[data[count][0]] = data[count][1];
count++;
}
for(var i = 1; i<=total_slides; i++){
for(var j = 1; j <= slidesnr_and_shapesnr[i]; j++){
for(var k = 0; k<data.length; k++){
if(data[k][0] == i && data[k][1] == j){
data_object['slide'+i]['shapes'+j] = {
'width': data[k][2],
'height': data[k][3],
'left': data[k][4],
'top': data[k][5],
'href': data[k][6]
}
}
}
}
}
我得到无法设置未定义的属性'shapes1'的原因可能是：
data_object['slide'+i]['shapes'+j] // this line我将以哪种方式创建所需的对象格式？
附言数据变量包含多个看起来相同的数组。是数组中的一个数组。
用于测试的其他一些数据是：
[ '1', '1', '964', '718', '0', '0', '0' ]
[ '2', '1', '964', '718', '0', '0', '0' ]
[ '2', '2', '311', '379', '612', '179', '0' ]
[ '2', '3', '35', '39', '36', '694', '0' ]
[ '2', '4', '35', '39', '75', '694', '0' ]
[ '3', '1', '964', '718', '0', '0', '0' ]
[ '3', '2', '116', '137', '46', '598', '16' ]
[ '3', '3', '35', '39', '181', '696', '0' ]
[ '3', '4', '35', '39', '220', '696', '0' ]
[ '3', '5', '35', '39', '259', '696', '0' ]
[ '3', '6', '35', '39', '297', '696', '0' ]
[ '3', '7', '35', '39', '337', '696', '0' ]
[ '3', '8', '51', '51', '658', '541', '0' ]
[ '3', '9', '51', '51', '787', '541', '0' ]
[ '4', '1', '964', '718', '0', '0', '0' ]
[ '4', '2', '116', '137', '46', '598', '62' ]
[ '4', '3', '35', '39', '181', '696', '0' ]
[ '4', '4', '35', '39', '221', '696', '0' ]
[ '4', '5', '35', '39', '260', '696', '0' ]
[ '4', '6', '35', '39', '298', '696', '0' ]
[ '4', '7', '56', '56', '894', '260', '0' ]
[ '5', '1', '964', '718', '0', '0', '0' ]
[ '5', '2', '116', '137', '46', '598', '24' ]
[ '5', '3', '35', '39', '181', '696', '0' ]
[ '5', '4', '35', '39', '298', '696', '0' ]
[ '5', '5', '35', '39', '221', '696', '0' ]
[ '5', '6', '35', '39', '260', '696', '0' ]
最佳答案
将其放在违规行的前面：
if (!data_object['slide'+i]) {
data_object['slide'+i] = {};
}