c# - 可重用的代码，使双击时矩形的不透明度为零

当您双击屏幕所在的位置时，我有一些要使其“出现”的矩形：

<StackPanel>
    <Rectangle Name="MyRect1" Opacity="0" Height="100" DoubleTapped="MyRect1_DoubleTapped" Fill="Aqua" />
    <Rectangle Name="MyRect2" Opacity="0" Height="100" DoubleTapped="MyRect2_DoubleTapped" Fill="Black"/>
    <Rectangle Name="MyRect3" Opacity="0" Height="100" DoubleTapped="MyRect3_DoubleTapped" Fill="Blue"/>
</StackPanel>

我当前的背后代码-可以工作：

private void MyRect1_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    MyRect1.Opacity = 1;
}

private void MyRect2_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    MyRect2.Opacity = 1;
}

private void MyRect3_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    MyRect3.Opacity = 1;
}

由于我可能想要一打或更多这些出现的矩形，是否有什么方法可以对所有这些矩形使用一个事件处理程序？

即不是每个矩形都有处理程序，而是类似：

<StackPanel>
    <Rectangle Name="MyRect1" Opacity="0" Height="100" DoubleTapped="MyRect_DoubleTapped" Fill="Aqua" />
    <Rectangle Name="MyRect2" Opacity="0" Height="100" DoubleTapped="MyRect_DoubleTapped" Fill="Black"/>
    <Rectangle Name="MyRect3" Opacity="0" Height="100" DoubleTapped="MyRect_DoubleTapped" Fill="Blue"/>
</StackPanel>

使用单个处理程序MyRect_DoubleTapped：

private void MyRect_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    (some way to tell which rectangle was DoubleTapped)
    (the identified rectangle).Opacity = 1;
}

最佳答案

您可以使用sender来了解被窃听的是哪一个

private void MyRect_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    Rectangle myRect = (Rectangle)sender;
    myRect.Opacity = 1;
}

sender是引发事件的对象。

关于c# - 可重用的代码，使双击时矩形的不透明度为零，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/43454710/