我在两个不同的QMainWindow上创建了两个QPushButton。我将以特定的时间间隔将焦点随机分配给它们。以下是代码。
int main(int argc, char **argv){
QApplication a(argc, argv);
QMainWindow *win1= new QMainWindow();
win1->resize(567,578);
win1->move(67,30);
win1->show();
QMainWindow *win2= new QMainWindow();
win2->resize(567,578);
win2->move(97,580);
win2->show();
win1->show();
//win2->setModal(true);
QPushButton *but1 = new QPushButton(win1);
but1->resize(80,20);
but1->move(100,100);
but1->setText("1");
but1->show();
QPushButton *but2 = new QPushButton(win2);
but2->resize(80,20);
but2->move(100,300);
but2->setText("2");
but2->show();
while(1){
if((rand()%2) == 1){
//win2->lower();
win1->raise();
win1->activateWindow();
win1->setWindowState(Qt::WindowActive);
win1->setFocus(Qt::ActiveWindowFocusReason);
but1->setFocus(Qt::ActiveWindowFocusReason);
}
else{
//win1->lower();
win2->raise();
win2->activateWindow();
win2->setFocus(Qt::ActiveWindowFocusReason);
but2->setFocus(Qt::ActiveWindowFocusReason);
}
qApp->processEvents(0x00);
sleep(2);
}
但是问题在于,第一个窗口的标题栏没有改变颜色(通常,将窗口从视觉堆栈后移到n处会更改标题栏的颜色),即使它在视觉上已成为顶部窗口
最佳答案
如果将上一个循环更改为类似的内容,则将获得所需的行为:
while (1) {
// Exits if both windows are closed
if (!win1->isVisible() && (!win2->isVisible())) {
return 0;
}
// Eventually changes the focus, if the desired window is still visible
if((rand() % 2) == 1) {
if (win1->isVisible()) {
QApplication::setActiveWindow(win1);
}
}
else {
if (win2->isVisible()) {
QApplication::setActiveWindow(win2);
}
}
QTime now;
now.start();
do {
qApp->processEvents(0x00);
} while (now.elapsed() < 2000);
}
无论如何,如果使程序进入睡眠状态,则在此间隔内它不会响应用户输入,因此请当心。
该实现非常丑陋,但是它检查要聚焦的窗口是否仍然可见(即用户尚未关闭窗口),如果两个窗口都已关闭,则最终退出。
当然,我想您只是对setActiveWindow()感兴趣,所以我没有花太多时间写一些漂亮的东西!