我有以下代码,它根据用户的登录详细信息从表中获取数据

//==========================================
//  CONNECT TO THE LOCAL DATABASE
//==========================================
$user_name = "xxxx";
$pass_word = "xxxxx";
$database = "xxxx";
$server = "xxxxxx";

$db_handle = mysql_connect($server, $user_name, $pass_word);
$db_found = mysql_select_db($database, $db_handle);

if ($db_found) {
    $SQL = "SELECT * FROM students WHERE L1 = '$uname' AND L2 = '" .md5 ($_POST['password'])."'";
    $result = mysql_query($SQL);
    $num_rows = mysql_num_rows($result);

    //====================================================
    //  CHECK TO SEE IF THE $result VARIABLE IS TRUE
    //====================================================

    if ($result) {
        if ($num_rows > 0) {
            $color="1";

            $result = mysql_query("SELECT * FROM entry, students   WHERE entry.studentName = students.studentName AND students.L1='$uname' ") or die(mysql_error());

            echo "<p>Welcome "; echo $row[studentName];
            echo "<p>You records as of ";
            echo date('l jS \of F Y h:i:s A');

            echo "<table border='1' cellpadding='2' cellspacing='0'>";
            echo "<tr> <th>Date</th><th>Student Name</th> <th>Tutor name</th> <th>Procedure name</th> <th>Grade</th><th>Student Reflection</th><th>Tutor Comments</th><th>Professionalism</th> <th>Communication</th> <th>Alert</th> <th>Dispute</th> </tr>";
            // keeps getting the next row until there are no more to get

            while($row = mysql_fetch_array( $result )) {
                if($color==1){
                    echo "<tr bgcolor=#DDD ><td>".$row['date']."</td><td>".$row['studentName']."</td><td>".$row['tutorName']."</td><td>".$row['procedureName']."</td><td>".$row['grade']."</td><td>".$row['studentReflection']."</td><td>".$row['tutorComments']."</td><td>".$row['professionalism']."</td><td>".$row['communication']."</td><td>".$row['alert']."</td><td>".$row['dispute']."</td></tr>";

                    // Set $color==2, for switching to other color
                    $color="2";
                }
                // When $color not equal 1, use this table row color
                else {
                    echo "<tr bgcolor='#CCC'><td>".$row['date']."</td><td>".$row['studentName']."</td><td>".$row['tutorName']."</td><td>".$row['procedureName']."</td><td>".$row['grade']."</td><td>".$row['studentReflection']."</td><td>".$row['tutorComments']."</td><td>".$row['professionalism']."</td><td>".$row['communication']."</td><td>".$row['alert']."</td><td>".$row['dispute']."</td></tr>";
                    // Set $color back to 1
                    $color="1";
                }
            }
            echo '</table>';
        }

我想做的是在表上方回显或打印出用户名,但我很难这样做。我唯一想让它工作的是将它添加到while循环中,但是它会打印出用户有记录的次数。
你能帮忙吗?

最佳答案

您需要获取第一行才能访问用户信息。这意味着您必须在循环之前调用mysql_fetch_array一次。
这会给你带来麻烦,因为你还需要在循环中调用它。您可以使用各种布尔标志或行的副本来绕过它,但最好的方法是稍微更改代码的结构。
使用do-while loop,结合if statement。这允许您首先获取一行,如果找不到任何行,则执行特殊操作。之后,您将得到一个循环,它将执行现在的操作,只检查迭代之后是否有下一行,而不是之前,否则将跳过表输出中的第一行。

if ($row = mysql_fetch_array( $result )) {
  // Print user info
  // Print table header

  do {

    // Print table row

  } while ($row = mysql_fetch_array( $result ));

  // Print table footer
}
else
{
  // User not found. Print error or whatever.
}

关于php - PHP和mysql查询以检索名称,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/13032169/

10-16 20:56