ios - XMPPFramework-如何创建MUC session 室并邀请用户？

我正在使用Robbiehanson的iOS XMPPFramework。我正在尝试创建一个MUC聊天室并邀请用户加入群聊聊天室，但是它不起作用。

我正在使用以下代码:

XMPPRoom *room = [[XMPPRoom alloc] initWithRoomName:@"[e-mail]/room" nickName:@"room"];
[room createOrJoinRoom];
[room sendInstantRoomConfig];
[room setInvitedUser:@"[e-mail]"];
[room activate:[self xmppStream]];
[room inviteUser:jid1 withMessage:@"hello please join."];
[room sendMessage:@"HELLO"];

用户[e-mail]应该会收到邀请消息，但没有任何反应。

任何帮助将不胜感激。 :)

最佳答案

在探索了各种解决方案之后，我决定在这里编译并分享我的实现:

创建XMPP session 室:

XMPPRoomMemoryStorage *roomStorage = [[XMPPRoomMemoryStorage alloc] init];

/**
 * Remember to add 'conference' in your JID like this:
 * e.g. [e-mail]
 */

XMPPJID *roomJID = [XMPPJID jidWithString:@"[e-mail]"];
XMPPRoom *xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:roomStorage
                                                       jid:roomJID
                                             dispatchQueue:dispatch_get_main_queue()];

[xmppRoom activate:[self appDelegate].xmppStream];
[xmppRoom addDelegate:self
        delegateQueue:dispatch_get_main_queue()];

[xmppRoom joinRoomUsingNickname:[self appDelegate].xmppStream.myJID.user
                        history:nil
                       password:nil];

检查是否在此委托(delegate)中成功创建了空间:

- (void)xmppRoomDidCreate:(XMPPRoom *)sender

检查您是否已加入此代表的 session 室:

- (void)xmppRoomDidJoin:(XMPPRoom *)sender

创建房间后，获取房间配置表:

- (void)xmppRoomDidJoin:(XMPPRoom *)sender {
    [sender fetchConfigurationForm];
}

配置您的房间

/**
 * Necessary to prevent this message:
 * "This room is locked from entry until configuration is confirmed."
 */

- (void)xmppRoom:(XMPPRoom *)sender didFetchConfigurationForm:(NSXMLElement *)configForm
{
    NSXMLElement *newConfig = [configForm copy];
    NSArray *fields = [newConfig elementsForName:@"field"];

    for (NSXMLElement *field in fields)
    {
        NSString *var = [field attributeStringValueForName:@"var"];
        // Make Room Persistent
        if ([var isEqualToString:@"muc#roomconfig_persistentroom"]) {
            [field removeChildAtIndex:0];
            [field addChild:[NSXMLElement elementWithName:@"value" stringValue:@"1"]];
        }
    }

    [sender configureRoomUsingOptions:newConfig];
}

参考:XEP-0045: Multi-User Chat，Implement Group Chat

邀请用户

- (void)xmppRoomDidJoin:(XMPPRoom *)sender
{
    /**
     * You can read from an array containing participants in a for-loop
     * and send multiple invites in the same way here
     */

    [sender inviteUser:[XMPPJID jidWithString:@"keithoys"] withMessage:@"Greetings!"];
}

在这里，您已经创建了XMPP多用户/群组聊天室，并邀请了一个用户。 :)