我试图将简单注册表中的数据插入到MySQL中。我的数据库托管在Amazon AWS RDS上,使用DBeaver对其进行编辑。当我运行代码时
受影响的行。“数据插入数据库。”;}否则{echo“一个
发生错误。未添加项。“;}$db->close()?>
我该怎么解决?我的PHP错了吗?我不知道我是否可以使用MySQLi,我如何确定?我假设Amazon RDS MySQL是兼容的。

<?php
// create short variable names
$name=$_POST['name'];
$birthdate=$_POST['birthdate'];
$email=$_POST['email'];
$password=$_POST['password'];
$address=$_POST['address'];
$city+$_POST['city'];

if (!get_magic_quotes_gpc()) {
    $name = addcslashes($name);
    $birthdate = addslashes($birthdate);
    $email = addcslashes($email);
    $password = addcslashes($password);
    $address = addcslashes($address);
    $city = addcslashes($city);
}

$host='xxxxxx'
$user='admin'
$password='xxxxx'
$dbname='users'
@ $db = mysqli_connect($host,$user,$password,$dbname)

if (mysqli_connect_errno()) {
    echo 'Error: Could not connect to database. Please try again later.';
    exit;
}

// Execute the query
$query = "INSERT INTO vestorinfo (name,birthdate,email,password,address,city)
    VALUES ('$_POST[name]','$_POST[birthdate]','$_POST[email]','$_POST[password]','$_POST[address]','$_POST[city]')";
$result = mysqli_query($query)
        or die ("Couldn't execute query."};

if ($result) {
    echo $db->affected_rows." data inserted into database.";
} else {
    echo "An error has occurred. The items were not added.";
}

$db->close();
?>

这是html页面上的表单
    <div id="registerform">
    <form action="php/registerprocess.php" method="post" class="form-horizontal">

<fieldset>

<!-- Form Name -->

<!-- Text input-->
<div class="form-group">
  <label class="col-md-4 control-label" for="name">Name</label>
  <div class="col-md-4">
  <input id="name" name="name" placeholder="Your name" class="form-control input-md" required="" type="text">

  </div>
</div>

<!-- Text input-->
<div class="form-group">
  <label class="col-md-4 control-label" for="birthdate">Birth Date</label>
  <div class="col-md-4">
  <input id="birthdate" name="birthdate" placeholder="07/04/1950" class="form-control input-md" required="" type="text">

  </div>
</div>

<!-- Text input-->
<div class="form-group">
  <label class="col-md-4 control-label" for="email">Email</label>
  <div class="col-md-4">
  <input id="email" name="email" placeholder="" class="form-control input-md" required="" type="text">

  </div>
</div>

<!-- Password input-->
<div class="form-group">
  <label class="col-md-4 control-label" for="password">Password</label>
  <div class="col-md-4">
    <input id="password" name="password" placeholder="" class="form-control input-md" required="" type="password">
    <span class="help-block">Must be &gt;= 8 characters including at least 1 number</span>
  </div>
</div>

<!-- Text input-->
<div class="form-group">
  <label class="col-md-4 control-label" for="email">Address</label>
  <div class="col-md-4">
  <input id="address" name="address" placeholder="" class="form-control input-md" required="" type="text">
  </div>
</div>

<!-- Text input-->
<div class="form-group">
  <label class="col-md-4 control-label" for="email">City</label>
  <div class="col-md-4">
  <input id="city" name="city" placeholder="" class="form-control input-md" required="" type="text">
  </div>
</div>
</div>

</fieldset>

最佳答案

您的代码存在sql注入的风险,您应该使用param binding而不是var作为$POST
不管怎么说,关于您的问题是缺少insert值
可能是因为你用错误的方式引用了$POST的索引
例句:使用连接,你应该

  $query = "INSERT INTO vestorinfo (name,birthdate,email,password,address,city)
      VALUES ('" . $_POST['name'] ." , " . $_POST['birthdate'] .", " .
      $_POST['email'] . "," . $_POST['password'] . "," .
         $_POST['address'] . "," . $_POST['city'] . ")";

关于php - 无法弄清楚为什么我的PHP没有插入MySQL DB,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/44704942/

10-09 20:11
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