javascript - jquery 1.4，同步请求

var path_data = path+"?q=map/get_data/"+param1+'/' +param2+'/'+param3+'/' +param4+'/' +param5;
var path_map_center = path+"?q=map/get_center/"+param1;

$.getJSON(path_map_center, function(data) {
   center_lati = data.lati;
   center_longi = data.longi;
});

//在我移至下一行代码之前，如何确保分配了center_lati center_longi。基本上如何等到上面执行。

最佳答案

在基于ajax的系统中，建议遵循异步开发，这意味着所有需要使用ajax调用返回的数据的代码都必须添加到各自的回调方法中

var path_data = path + "?q=map/get_data/" + param1 + '/' + param2 + '/' + param3 + '/' + param4 +'/' + param5;
var path_map_center = path + "?q=map/get_center/" + param1;

$.getJSON(path_map_center, function(data) {
    var center_lati = data.lati;
    var center_longi = data.longi;
    //all code that need to work with center_lati and center_longi should be added here
});
// do no put any ode that need to work with center_lati and center_longi should be added here

不过，如果您不打算使用异步模式，请使用async选项

var path_data = path + "?q=map/get_data/" + param1 + '/' + param2 + '/' + param3 + '/' + param4 + '/' + param5;
var path_map_center = path + "?q=map/get_center/" + param1;

$.ajax({
    url: path_map_center,
    dataType: 'json',
    type: 'GET',
    async: false,
    success: function (data) {
        center_lati = data.lati;
        center_longi = data.longi;
    }
})