是否可以在不知道泛型类型的参数的情况下创建其实例?我只有'class'类型,它是从Class.forName(classname)获得的;

//generic class

public class MappedField<T> extends Field {
    private T value;
    private String sourceName;

public MappedField(String name, String sourceName, FieldType type){
    super(name, type);
    this.sourceName = sourceName;
}

public MappedField(String name, String sourceName, FieldType type, boolean key){
    super(name, type, key);
    this.sourceName = sourceName;
}


}

//here's my situation

    String columnName = field.getSourceName() != null ? field.getSourceName() : field.getName();
            Class c = Class.forName(field.getType().getFullClassName());

            //I need like that if `field.getType() = "Integer"`: `MappedField<Integer> objField = new MappedField<Integer>(field)`;
            MappedField objField = new MappedField(field);

            objField.setValue(getField(c, rset, columnName));
            object.getValues().add(objField);


编辑:
就像我有“ java.lang.Integer”并想要获取MappedField

最佳答案

成功编译后,泛型类型将从类和接口中删除。在运行时无法检测到泛型类型。

参考链接:
Use reflection to create a generic parameterized class in Java

09-10 08:22
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