鉴于代码:
from i in this.GridViewFoo.SelectedItems
select new EmployeeEntity
{
EmployeeID = (i as EmployeeDto).EmployeeID,
Email = this.GetAllEmail((i as EmployeeDto).Email, (i as EmployeeDto).SecondaryEmails),
EmployeeNumber = (i as EmployeeDto).EmployeeNumber,
FirstName = (i as EmployeeDto).FirstName,
LastName = (i as EmployeeDto).LastName
}
在安全转换
(i as EmployeeDto)
之后,我可能会收到 NullReferenceException。我怎样才能确保代码的安全性,而不是用大量的空检查使他过载?解决方案概述:
我做了一些测试来断言解决方案是否有效。两者都运行良好并带来相同的结果,您可以检查 HERE 。之后我用 OfTypeSolution 和 letSolution 做了一些性能测试。
由于 OfType 解决方案平均有更好的时间,这将是答案!
最佳答案
您可以在 Select
之前使用 OfType :
from i in this.GridViewFoo.SelectedItems.OfType<EmployeeDto>()
select new EmployeeEntity
{
EmployeeID = i.EmployeeID,
Email = this.GetAllEmail(i.Email, i.SecondaryEmails),
EmployeeNumber = i.EmployeeNumber,
FirstName = i.FirstName,
LastName = i.LastName
}
它只会为您提供
EmployeeDto
中的 SelectedItems
类型项,因此无需强制转换和空检查。关于c# - 具有安全转换和空验证的 Linq,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/12497693/