我有这样的格式
2017-02-14T11:30:00
我想转换成
Fri Feb 14 11:30 PM
是的,我不知道是星期几,所以我输入“ Fri”,然后那个PM应该是AM
使用Javascript,我以前传递的是完全不同的数据,因此此功能需要更多修改
var getTravelDateFormatted = function () {
// Example Mon Jan 23
return function (str) {
var daysNames = ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'],
monthNames = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sept', 'Oct', 'Nov', 'Dec'],
d = new Date(str),
day = d.getDate(),
month = monthNames[d.getMonth()],
year = d.getFullYear().toString().substr(2, 2),
dayName = daysNames[d.getDay()];
//return day + '-' + month + '-' + year + ' (' + dayName + ')';
return dayName + ' ' + month + ' ' + day;
};
};
关于如何做到这一点的想法?
最佳答案
var getTravelDateFormatted = function() {
// Example Mon Jan 23
return function(str) {
var daysNames = ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'],
monthNames = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sept', 'Oct', 'Nov', 'Dec'],
d = new Date(str),
day = d.getDate(),
month = monthNames[d.getMonth()],
year = d.getFullYear().toString().substr(2, 2),
hours = d.getHours(),
minutes = d.getMinutes(),
dayName = daysNames[d.getDay()];
//return day + '-' + month + '-' + year + ' (' + dayName + ')';
return hours > 12 ? (dayName + ' ' + month + ' ' + day + ' ' + (hours - 12) + ":" + minutes + " PM"):
(dayName + ' ' + month + ' ' + day + ' ' + hours + ":" + minutes + " AM");
};
}();
var formatedDate = getTravelDateFormatted('2017-02-14T11:30:00');
console.log(formatedDate);