我是servlet的新手，我可以从servlet中获取数据，但无法向其中发送数据，我想在不使用提交表单的情况下执行此操作，请问我能得到一些帮助吗
单击该按钮，它将转到servlet并返回文本，但不返回发送给它的值
这是我的index.jsp
<!DOCTYPE html>
<html lang="en">
<head>
<title>SO question 4112686</title>
<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>
$(document).ready(function() {
$('#somebutton').click(function() {
$.get('GetUserServlet', function(responseText) {
$('#somediv').text(responseText);
});
});
});
$("#somebutton").click(function(){
$.ajax
(
{
url:'GetUserServlet',
data:{name:'abc'},
type:'get',
cache:false,
success:function(data){alert(data);},
error:function(){alert('error');}
}
);
}
);
</script>
</head>
<body>
<button id="somebutton" onclick="showHint('GetUserServlet.java', 'travis');">press here</button>
<div id="somediv"></div>
</body>
这是我的servlet
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String text = "Update Sucessful";
String name = request.getParameter("name");
response.setContentType("text/plain"); // Set content type of the response so that jQuery knows what it can expect.
response.setCharacterEncoding("UTF-8"); // You want world domination, huh?
response.getWriter().write( name + text); // Write response body.
最佳答案
您可以在此处使用$ .ajax()或$ .post。因为您已经使用$ .ajax()。请参考以下更正:
<!DOCTYPE html>
<html lang="en">
<head>
<title>SO question 4112686</title>
<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>
$(document).ready(function() {
$('#somebutton').click(function() {
$.get('GetUserServlet', function(responseText) {
$('#somediv').text(responseText);
});
});
});
$("#somebutton").click(function(){
$.ajax({
url:'GetUserServlet',
data:{name:'abc'},
type:'get',
cache:false,
success:function(data){
alert(data);
$('#somediv').text(responseText);
},
error:function(){
alert('error');
}
}
);
}
);
</script>
</head>
<body>
<button id="somebutton">press here</button>
<div id="somediv"> </div>
</body>
，您的servlet应该是:
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.*;
import javax.servlet.http.*;
public class GetUserServlet extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doPost(request, response);
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String text = "Update successfull"; //message you will recieve
String name = request.getParameter("name");
PrintWriter out = response.getWriter();
out.println(name + " " + text);
}