我正在尝试将MVVM模式应用于MVVM Light。我有一个数据绑定(bind)的ListBox ...
MainView.xaml [摘录]
<ListBox Name="recipesListBox"
ItemsSource="{Binding RecipeList}"
SelectedItem="{Binding SelectedRecipe, Mode=TwoWay}"
HorizontalAlignment="Stretch"
VerticalAlignment="Stretch"
Grid.Row="1"
Margin="12,0,12,0"
SelectionChanged="recipesListBox_SelectionChanged" >
MainViewModel.cs [摘录]
private Recipe selectedRecipe;
public Recipe SelectedRecipe
{
get
{
return selectedRecipe;
}
set
{
selectedRecipe = value;
RaisePropertyChanged("SelectedRecipe");
}
}
...在SelectionChanged上执行页面导航:
MainView.xaml.cs [摘录]
private void recipesListBox_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
string destination = "/RecipeView.xaml";
if (recipesListBox.SelectedIndex == -1) // If selected index is -1 (no selection) do nothing
return;
this.NavigationService.Navigate(new Uri(destination, UriKind.Relative));
//recipesListBox.SelectedIndex = -1; // Reset selected index to -1 (no selection)
}
////之后,您可以看到在页面导航后重置索引的旧代码-现在,对于绑定(bind)的数据,显然它还将我选择的项目设置为null!返回时,我该如何导航到新 View ,显示所选项目的属性并重置所选索引?谢谢!
最佳答案
我这样做的方式是这样的:
protected override void OnNavigatedFrom(System.Windows.Navigation.NavigationEventArgs e)
{
if (listBox.SelectedItem != null)
{
listBox.SelectedIndex = -1;
}
base.OnNavigatedFrom(e);
}
然后将以下内容添加到SelectionChanged事件
if(SelectedItem != null)
{
// Do something with SelectedItem
}
关于silverlight - ListBox SelectedItem绑定(bind)到: page navigation,获取项,在新 View 中显示其属性并重置SelectedIndex。我能怎么做?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/11002049/