我正在尝试将管道连接到cmd.ExtraFiles
我目前有错误的说法
cannot use cmdstdout (type io.ReadCloser) as type []byte in argument to pipeR.Read
cannot use cmdstdout (type io.ReadCloser) as type []byte in argument to fd3.Write
这是我到目前为止拥有的gocode
cmd2 = exec.Command("-i", "pipe:0", "-i", "pipe:1")
cmd1 := exec.Command("command", "-o", "-")
pipeR, pipeW, _ := os.Pipe()
cmd2.ExtraFiles = []*os.File{
pipeW,
}
cmd1.Start()
cmd1stdout, err := cmd1.StdoutPipe()
if err != nil {
log.Printf("pipeThruError: %v\n", err)
return err
}
fd3 := os.NewFile(3, "/proc/self/fd/3")
fd3.Write(cmd1stdout)
pipeR.Read(cmd1stdout)
pipeR.Close()
pipeW.Close()
fd3.Close()
cmd3 = exec.Command("command", "-o", "-")
stdin, stdinErr := cmd3.StdoutPipe()
if stdinErr != nil {
log.Printf("pipeThruFStdinErr: %v\n", stdinErr)
return stdinErr
}
cmd3.Start()
cmd2.Stdin = stdin
编辑:添加了完整范围
目标是让cmt2通过
Stdin
通过cmd3接受输入,并通过ExtraFiles
通过cmd1输出输出 最佳答案
这里的类型不太一致。具体来说,
cmd.StdoutPipe
返回
io.ReadCloser
然而
pipeR.Read
期望输入
[]byte
。我相信您最终希望利用Read的Write和os package函数来完成任务,如下所示:
package main
import (
"log"
"os"
"os/exec"
)
func main() {
cmd := exec.Command("command", "-o", "-")
pipeR, pipeW, _ := os.Pipe()
cmd.ExtraFiles = []*os.File{
pipeW,
}
cmd.Start()
cmdstdout, err := cmd.StdoutPipe()
if err != nil {
log.Printf("pipeThruError: %v\n", err)
os.Exit(1)
}
buf := make([]byte, 100)
cmdstdout.Read(buf)
pipeR.Close()
pipeW.Close()
fd3 := os.NewFile(3, "/proc/self/fd/3")
fd3.Write(buf)
fd3.Close()
}
关于go - 尝试通过管道传递到cmd.ExtraFiles时失败,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/54412764/