我正在写一个函数,使输入变得很慢。
var vslug = function (str) {
str = str.replace(/^\s+|\s+$/g, '');
str = str.toLowerCase();
var vregex = /(?:\.([^.]+))?$/;
var filename = str.replace(vregex.exec(str)[0],'');
var extension = vregex.exec(str)[1];
var from = "àáäâèéëêìíïîıòóöôùúüûñçşğ·/,:;";
var to = "aaaaeeeeiiiiioooouuuuncsg_____";
for (var i = 0; i < from.length; i++) {
console.log('before ' + str);
str = filename.replace(new RegExp(from[i], 'g'), to[i]);
console.log('after ' + str);
}
str = str.replace(/[^a-z0-9 _-]/g, '')
.replace(/\s+/g, '_')
.replace(/-+/g, '_');
if (typeof extension !== "undefined") {
return str+'.'+extension;
} else {
return str;
}
};
我不能做这部分-我失明了。任何帮助表示赞赏。
var from = "àáäâèéëêìíïîıòóöôùúüûñçşğ·/,:;";
var to = "aaaaeeeeiiiiioooouuuuncsg_____";
for (var i = 0; i < from.length; i++) {
console.log('before ' + str);
str = filename.replace(new RegExp(from[i], 'g'), to[i]);
console.log('after ' + str);
}
最佳答案
filename
不变-变量命名相同的字符串,并且该字符串无法修改。这样,每个循环在使用filename.replace..
时都会再次开始处理原始字符串。
相反,请消除filename
(或将其完全集成)并使用str = str.replace..
str = str.replace(vregex.exec(str)[0],'');
for (var i = 0; i < from.length; i++) {
str = str.replace(new RegExp(from[i], 'g'), to[i]);
// ^-- next loop gets new value
}
(此外,这可以通过替换函数和映射而不是n循环来处理,并且可能有JavaScript的Unicode库可用。)
使用映射和替换功能的方法可能类似于:
// Specify map somewhere reusable; can be built from paired arrays for simplicity.
var replacements = {"à":"a", "á":"a", .. ";":"_"}
// Object.keys is ES5, shim as needed. e.g. result: [à;á..]
var alternation = "[" + Object.keys(replacements).join("") + "]"
// This regex will match all characters we are trying to match.
var regex = new Regex(alternation, "g")
str = str.replace(regex, function (m) {
var r = replacements[m]
return r || m
})
见String.replace(regex, function)
关于javascript - 具有非拉丁字符的Javascript段函数,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/20981537/