我正在写一个函数,使输入变得很慢。

var vslug = function (str) {
  str = str.replace(/^\s+|\s+$/g, '');
  str = str.toLowerCase();
  var vregex = /(?:\.([^.]+))?$/;
  var filename  = str.replace(vregex.exec(str)[0],'');
  var extension = vregex.exec(str)[1];
  var from = "àáäâèéëêìíïîıòóöôùúüûñçşğ·/,:;";
  var to   = "aaaaeeeeiiiiioooouuuuncsg_____";
  for (var i = 0; i < from.length; i++) {
    console.log('before ' + str);
    str = filename.replace(new RegExp(from[i], 'g'), to[i]);
    console.log('after ' + str);
  }
  str = str.replace(/[^a-z0-9 _-]/g, '')
  .replace(/\s+/g, '_')
  .replace(/-+/g, '_');
  if (typeof extension !== "undefined") {
    return str+'.'+extension;
  } else {
    return str;
  }
};


我不能做这部分-我失明了。任何帮助表示赞赏。

  var from = "àáäâèéëêìíïîıòóöôùúüûñçşğ·/,:;";
  var to   = "aaaaeeeeiiiiioooouuuuncsg_____";
  for (var i = 0; i < from.length; i++) {
    console.log('before ' + str);
    str = filename.replace(new RegExp(from[i], 'g'), to[i]);
    console.log('after ' + str);
  }

最佳答案

filename不变-变量命名相同的字符串,并且该字符串无法修改。这样,每个循环在使用filename.replace..时都会再次开始处理原始字符串。

相反,请消除filename(或将其完全集成)并使用str = str.replace..

str = str.replace(vregex.exec(str)[0],'');
for (var i = 0; i < from.length; i++) {
  str = str.replace(new RegExp(from[i], 'g'), to[i]);
  // ^-- next loop gets new value
}


(此外,这可以通过替换函数和映射而不是n循环来处理,并且可能有JavaScript的Unicode库可用。)



使用映射和替换功能的方法可能类似于:

// Specify map somewhere reusable; can be built from paired arrays for simplicity.
var replacements = {"à":"a", "á":"a", .. ";":"_"}
// Object.keys is ES5, shim as needed. e.g. result: [à;á..]
var alternation = "[" + Object.keys(replacements).join("") + "]"
// This regex will match all characters we are trying to match.
var regex = new Regex(alternation, "g")

str = str.replace(regex, function (m) {
    var r = replacements[m]
    return r || m
})


String.replace(regex, function)

关于javascript - 具有非拉丁字符的Javascript段函数,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/20981537/

10-12 05:52
查看更多