我们想将单词包装在换行符（\ n）处的字符串中。基本上，我们按ENTER键开始换行。
按下Enter键即可在“我们的消息”中创建新行。
输入数据 ：
在注释列中捕获了字符串。
给出的评论栏为：
EDI ORDER-SAVE COMMENTS\nC3 Generic\nLOC 0833\nExpected arrival 01/07/2016\nOTYPE NE\nTRKPC 01 GM/00007643020008361321
我们尝试过：
string s = "EDIORDER-SAVE COMMENTS C3 Generic LOC 0833 Expected arrival 01/07/2016 OTYPE NE TRKPC 01 GM/00007643020008361321" ;
StringBuilder sb = new StringBuilder(s);
int i = 0;
while ((i = sb.indexOf(" ", i + 20)) != -1) {
sb.replace(i, i + 1, "\n");
}
转换后的预期数据：
换行符是换行符
Long String of Comment field should Splits in 6 different lines
EDI ORDER-SAVE COMMENTS
C3 Generic
LOC 0833
Expected arrival 01/07/2016
OTYPE NE
TRKPC 01 GM/00007643020008361321
输出后的确切数据如下所示：
SalesOrder NComment SalesOrderLine StockCode
183590 EDI ORDER-SAVE COMMENTS 1
183590 2 abc-defg-13OZ-24
183590 C3 Generic 37
183590 LOC 0833 38
183590 Expected arrival 01/07/2016 39
183590 OTYPE NE 40
183590 TRKPC 01 GM/00007643020008361321 51
任何帮助，将不胜感激！
最佳答案
抱歉，我还没有真正想要实现的目标。您要在通过第20个字符的单词之前插入中断吗？
StringBuilder sb = new StringBuilder(s);
int currentSpaceFound = sb.indexOf(" ");
int i = 1;
while (currentSpaceFound != -1) {
int lastOccurence = currentSpaceFound;
currentSpaceFound = sb.indexOf(" ", currentSpaceFound + 1);
if (currentSpaceFound > (20 * i)) {
sb.setCharAt(lastOccurence, '\n');
i++;
}
}
System.out.println(sb);