c - 将字符串分成C部分

我已经很久没有用C语言编写程序了，我有一个类似下面的字符串

"VRUWFB02=I.V.R, W.F.B, plan 2, VRUWFB01=I.V.R, W.F.B, plan 1, assa=784617896.9649164, plan24, massmedua=plan12, masspedia=IVR, masojh, jhsfdkl, oijhojomn, oiafofvj, plan"

我需要在“=”之前找到，比如VRUWFB02，VRUWFB01，assa，massmedua，masspedia。
我可以断开字符串，但无法提取那些特定的单词。
有人能帮我吗

char st[] = "VRUWFB02=I.V.R, W.F.B, plan 2, VRUWFB01=I.V.R, W.F.B, plan 1,assa=784617896.9649164, plan24, massmedua=plan12, masspedia=IVR, masojh, jhsfdkl, oijhojomn, oiafofvj, plan";
char *ch;
regex_t compiled;
char pattern[80] = "  ";
printf("Split \"%s\"\n", st);
ch = strtok(st, " ");
while (ch != NULL) {
    if(regcomp(&compiled, pattern, REG_NOSUB) == 0) {
        printf("%s\n", ch);
    }
    ch = strtok(NULL, " ,");
}
return 0;

最佳答案

下面是一个我制作的快速示例程序来解释：

#include <string.h>
#include <stdio.h>

int main(void)
{
    char s[] = "VRUWFB02=I.V.R, W.F.B, plan 2, VRUWFB01=I.V.R, W.F.B, "
               "plan 1, assa=784617896.9649164, plan24, massmedua=plan12, "
               "masspedia=IVR, masojh, jhsfdkl, oijhojomn, oiafofvj, plan";
    char *p;
    char *q;

    p = strtok(s, " ");
    while (p)
    {
        q = strchr(p, '=');
        if (q)
            printf("%.*s\n", (int)(q - p), p);
        p = strtok(NULL, " ");
    }

    return 0;
}

输出：

$ ./example
VRUWFB02
VRUWFB01
assa
massmedua
masspedia

基本思想是用空格分隔字符串，然后在块中查找=字符。如果其中一个出现，则打印该块的所需部分。