我试图在控制台中每行打印80个字符。我可以每行打印80个字符，但是当字符串中剩余的字符少于80个时，就不会打印它们。我该如何补救？
public void output(String plainText, String cipherText, String iv, String key, String filename) {
System.out.println("CBC Vigenere by ");
System.out.println("Plaintext file name: " + filename);
System.out.println("Vigenere Keyword: " + key);
System.out.println("Initialization vector: " + iv + "\n");
//This is the code for printing 80 char per line
System.out.println("Clear Text: \n");
int j = 0;
String output = "";
for (int i = 0; i < plainText.length(); i++) {
j++;
output = output + plainText.charAt(i);
if (j == 80) {
System.out.println(output);
output = "";
j=0;
}else{
//an attempt to print the remaining characters
// System.out.println(output);
}
}
//same process as above.
System.out.println(" \n Cipher Text:\n ");
j = 0;
output = "";
for (int i = 0; i < cipherText.length(); i++) {
j++;
output = output + cipherText.charAt(i);
if (j == 80) {
System.out.println(output);
output = "";
j = 0;
} else if ((cipherText.length() - i) <= 80) {
if (j == 80) {
if (j == (cipherText.length() - i)) {
//if (j == 80) {
System.out.println(output);
output = "";
j = 0;
System.out.println((output));
j = 0;
}
}
}
}
System.out.println("\n\nNumber of characters in clean plaintext file: " + (plainText.length() - padding));
System.out.println("Block Size: " + key.length());
System.out.println("Number of pad Characters added: " + padding);
}
输出：
Clear Text:
csthesciencethatdealswiththetheoryandmethodsofprocessinginformationindigitalcomp
utersthedesignofcomputerhardwareandsoftwareandtheapplicationsofcomputersitthedev
elopmentimplementationandmaintenanceofcomputerhardwareandsoftwaresystemstoorgani
zeandcommunicateinformationelectronicallyabbreviationitcomputersaremanmadetoolst
hataidusinsolvingotherproblemsabiologististryingtofigureouthowlifeworksphysicist
sandchemistsaretryingtofigureouthowitemsreactinouruniversemathematiciansaretryin
gtofigureoutrulesformanmadesystemsanyresearchproblemthatmayimproveacomputerscapa
bilityofhelpingsolveaproblemoranyresearchproblemthatshedslightaboutanewwaytodoso
methingwithacomputerispartofcsmostexcitingresearchmedicalapplicationsexpertsyste
msfordiagnosisremotesurgerynanodeviceswithcomputingpowertodelivermedicineetcwene
edhelptryingtocreateacomprehensiveemraccessibletotherightpeopleonlycarsthatcandr
ivethemselvesseemslikethebestwayweknowhowtosolvelotsofproblemsisbythrowinglotsof
computingpowerattheminsteadoflookingforelegantsolutionsthisdoesntsoundexcitingbu
titwillbeexcitingwhentheresultsareachievediewatsoncsstudentstendtofindjobswheret
heyprogramatleastsomeintheprocesstheyaresolvingproblemschallengesitsimpossibleto
teachallthenewlanguagestoysultimatelywejustneedtoteachourstudentshowtothinksotha
ttheycanpickupnewthingsontheirownourbiggestchallengeisgettingthemtobuyintothatet
Cipher Text:
qiqxbxknvieuejlkvwcpbtquevshswdsbyitsndorkbkwxswngygxwrkgfsbqvxwmsgiatpheilbuxnu
ovzuyvmhwtvjiedrmnfkglrkfsddglexlsvsqfqjxiiqcbcqnyjvblktkjfeeaqklehghsfsutuiftqw
bpwmpyjzytumfgqbqjqzluspcjjzdaovvqeczpilbicjnibqzbcjavhqrqmdmhtgegjgjscscoxnkvel
kxrsbcwwpyjoswsihdtzrtyunqhczoipglabjjbcgkotmfovvwkseieszmvovataazltsolwviveqxpy
dgdosztziuhqztoobkbzmyixdgvsosvbkxctpjokdkdjizcncjozbbznupuepihytkwguytvhbgrphoi
nqhbqqbkqkqkxjikgqvlimdzsntmeifjtfwvwhphntudutoppoqjfmqlpxifiutoappzehyhfgqhondi
qjlwakbjmfngliduchxgqokirtcththfafhamzxzihgruoskadlxlmsnlvqljihejqqaluhwhifioqky
sokekkfxtjlgabnbiukgrdpzxsimdlkgpfaflnjxxuvqdjodosvtuiftemtahbokjmjudggknqnmxiwe
pqpfearegfundjwgxhigxgtorpmcvcoynzyehuhkbyzkywfvokhwrmauscozgppxpnkijunryqyqdqdc
wciygjvrimdmsmqyjujgiigwrvwqdlywjzyjjjmzmovkohpiedramexdxzhlzbbnzhkszcoxzjztcfwr
hcvonlnksamomkvjgrgdnnihegpvaqzgbsmmkuteeedulnworpfbdrqgqdbzxsiochhroqnrbzbjiesd
hgshgtztkmmylywkpkhaymybjkukuobuegvbqfebhcccxvzhrdrdmqipdyvkokdklqlfjbmrgfybybto
ckvhwildyateedleltwnlikjvrfnrgmcdsxgjchozamigjffxhxxssrtfjeuzgybybtdnoythjhzbnjp
jfjjycqlbxfhuijdwhkteusgqspuhvgdeplzzpksvdkpnxnxisrsqtreczczclwwwsiictspapdeodze
nqsnqjdikcrdjpqpqpljwzqaemalvvgvfwtiyqwcvynbcwptnpvigcfmtulnwijuikikxetasahjzvzr
zdgnuvmomdxyicakuyvgishtczbbtciwpxaqfuqlrlrgcsmthuscbrwtutuvehyixxsbsxsmhhyhtihq
hrvdanhidymqnnhzkayqseralbznomjqdmelmbzpkpkzyhqabvohdhqtqufpsqgczdumvsknkjkyrzca
我缺少字符串中的最后20个字符。添加它们的实际方法是什么？字符串大小会有所不同，因此其大小并不总是相同。
最佳答案
如果output循环完成后for不为空，请打印它。