我有一个android设备,它创建一个json格式的消息并将其发送到tomcat服务器。服务器正在运行一个java web应用程序,它接收这个json格式的消息,然后处理它。
我的问题是,当服务器接收到消息时,服务器将某些字符('{'、'['、''、']、']'和'}')替换为其十六进制表示形式,这将导致服务器无法识别消息的JSON错误。
我的问题是,是否有人知道是什么引起了这个问题,以及我将如何着手解决这个问题(我确信这不是JSON代码,而是按照发送/接收的方式来处理消息)。
这是我的服务器端代码:

@Override
protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    // Setup response
    PrintWriter out = response.getWriter();

    // Store input message as String
    StringBuilder sb = new StringBuilder();
    String message;

    // Build String
    while ((message = request.getReader().readLine()) != null) {
        sb.append(message);
    }

    // Full message as String
    message = sb.toString();

    // Convert message to JSON format
    Gson gson = new Gson();
    ImageFeatures features = gson.fromJson(message, ImageFeatures.class);

    out.println("Normal data: " + features);
    out.println();
}

以下是我收到的错误:
com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected BEGIN_OBJECT but was STRING at line 1 column 12
com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$Adapter.read(ReflectiveTypeAdapterFactory.java:176)
com.google.gson.Gson.fromJson(Gson.java:795)
com.google.gson.Gson.fromJson(Gson.java:761)
com.google.gson.Gson.fromJson(Gson.java:710)
com.google.gson.Gson.fromJson(Gson.java:682)

这是在android设备将消息发送到服务器之前生成的json格式的消息:
{
"image_x_size":800,
"image_y_size":1600,
"features":
    [
        {"cart_x":5.0,"cart_y":124.0,"polar_angle":0.0,"polar_dist":0.0,"size":15.0},
        {"cart_x":5.0,"cart_y":124.0,"polar_angle":0.0,"polar_dist":0.0,"size":15.0}
    ]
}

这是服务器看到消息的方式(即message字符串的内容):
%7B+%09%22image_x_size%22%3A800%2C+%09%22image_y_size%22%3A1600%2C+%09%22features%22%3A+%09%09%5B+%09%09%09%7B%22cart_x%22%3A5.0%2C%22cart_y%22%3A124.0%2C%22polar_angle%22%3A0.0%2C%22polar_dist%22%3A0.0%2C%22size%22%3A15.0%7D%2C+%09%09%09%7B%22cart_x%22%3A5.0%2C%22cart_y%22%3A124.0%2C%22polar_angle%22%3A0.0%2C%22polar_dist%22%3A0.0%2C%22size%22%3A15.0%7D+%09%09%5D+%7D+

如您所见,消息字符串有各种十六进制值来替换某些字符。
多谢提前!
编辑:我想我应该包括我的android代码以进一步澄清
HttpClient http_client = new DefaultHttpClient();

// Set long timeout limit
HttpConnectionParams.setConnectionTimeout(http_client.getParams(), 10000);
HttpConnectionParams.setSoTimeout(http_client.getParams(), 10000);
HttpResponse response;

// Setup json_object
JSONObject json_object = convertImageFeaturesToJSON(data, x, y);

try {
HttpPost http_post = new HttpPost(URL_BASE + "/featureuploader");

Log.i(TAG, json_object.toString());

StringEntity se = new StringEntity(json_object.toString());
se.setContentType("application/json; charset=UTF-8");
se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json; charset=UTF-8"));

http_post.setEntity(se);
http_post.setHeader("Accept", "application/json");
http_post.setHeader("Content-Type", "application/json");

response = http_client.execute(http_post);

if (response != null) {
    String response_string = httpResponseToString(response.getEntity().getContent());
    if (! response_string.startsWith("Received: <html>")) {
        Log.i(TAG, "Received: ERROR! - " + response_string.substring(0, 20));
    } else {
        Log.i(TAG, "Received: " + response_string);
    }
} else {
    Log.e(TAG, "Did not receive from server");
}
} catch (Exception e) {
    Log.e(TAG, "Error: " + e.getMessage());
}

最佳答案

这就是服务器看到消息的方式…
这是服务器上看到的json的url编码版本。您需要先解码它(使用类似于URLDecoder的东西),或者以解码后的方式从请求中检索它。

10-07 18:57
查看更多