arrays - 从配置文件创建Powershell菜单

我一直在尝试从Powershell中的配置文件构建菜单。菜单的目的是调用其他脚本和可执行文件，并使维护更加容易，因此，每当需要添加菜单项时，我都可以轻松地更新配置。

最佳答案

首先，我强烈建议您使用XML格式的配置文件。它真的很有用。我想出了这样的解决方案:

#Assuming this is content of your XML config file. You could easily add new Ids to insert new actions.
[xml]$Config=@"
<?xml version="1.0"?>
<Menu>
    <Actions>
        <Id>
            <Choice>1</Choice>
            <Script>C:\DoThis.ps1</Script>
            <Description>Will do this</Description>
        </Id>
        <Id>
            <Choice>2</Choice>
            <Script>C:\DoThat.ps1</Script>
            <Description>Will do that</Description>
        </Id>
    </Actions>
</Menu>
"@

#Here's the actual menu. You could add extra formating if you like.

$Message = ''
$Continue = $true

DO
{
    cls
    Write-Host 'Welcome to the menu!'
    Write-Host ''

    if ($Message -ne '')
    {
        Write-Host ''
    }

    foreach ($Item in @($Config.Menu.Actions.Id))
    {
        Write-Host ("{0}.`t{1}." -f $Item.Choice,$Item.Description)
    }
    Write-Host ''
    Write-Host "Q.`tQuit menu."
    Write-Host ''

    $Message = ''
    $Choice = Read-Host 'Select option'
    if ($Choice -eq 'Q'){$Continue = $false} #this will release script from DO/WHILE loop.

    $Selection = $Config.Menu.Actions.Id | ? {$_.Choice -eq $Choice}
    if ($Selection)
    {
        cls
        Write-Host ("Starting {0}" -f $Selection.Description)
        & $Selection.Script
        Write-Host ''
    }
    else
    {
        $Message = 'Unknown choice, try again'

    }
    if ($Continue)
    {
        if ($Message -ne '')
        {
            Write-Host $Message -BackgroundColor Black -ForegroundColor Red
        }
        Read-Host 'Hit any key to continue'
    }
    cls
}
WHILE ($Continue)
Write-Host 'Exited menu. Have a nice day.'
Write-Host ''

输出:

Welcome to the menu!

1.  Will do this.
2.  Will do that.

Q.  Quit menu.

Select option:

关于arrays - 从配置文件创建Powershell菜单，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/38522043/