我已经编写了一个SQL查询,并试图使其适应Sequelize,但无法弄清楚如何在同一张表上创建关联。这是SQL:

SELECT t1.*
FROM `configurations` t1
INNER JOIN
(
    SELECT max(configuration_start) maxConfigStart, pb_id
    FROM `configurations`
    WHERE
        active = 1
        AND DATE(configuration_start) <= DATE(NOW())
    GROUP BY `pb_id`
) t2
  ON t1.`pb_id` = t2.`pb_id`
  AND t1.`configuration_start` = t2.`maxConfigStart`
WHERE t1.`active` = 1
ORDER BY t1.`configuration_start` DESC


这是模型定义:

configurations = sequelize.define 'configurations', {
  id:
    type: Sequelize.INTEGER
    primaryKey: true
    autoIncrement: true
  configuration_name: Sequelize.STRING
  configuration_start: Sequelize.DATE
  configuration_end: Sequelize.DATE
  created: Sequelize.DATE
  updated: Sequelize.DATE
}, {
  timestamps: false,
  scopes: {
    currentConfigTimes: {
      attributes: ['pb_id', [sequelize.fn('max', sequelize.col('configuration_start')), 'configuration_start']]
      where:
        active: 1
        configuration_start:
          lte: new Date()
      group: ['pb_id']
    },
    currentConfigIds: {
      attributes: ['pb_id', 'configuration_start', 'id']
      where:
        active: 1
        configuration_start:
          lte: new Date()
      order: [['configuration_start', 'DESC']]
    }
  }
}


有人可以提供的任何帮助将不胜感激。本质上,我正在尝试获取每个pb_id的最新过去配置。也许有更好的方法吗?

最佳答案

看来当前使用Sequelize实际上是不可能的。在花费大量时间阅读他们的文档以尝试了解实现此目标的最佳方法之后,我遇到了this Github issue试图解决完全相同的问题。最好的解决方案是此时使用原始查询。

10-06 05:12
查看更多