@Entity
@Table(name = "jobitems")
@IdClass(JobItemId.class)
public class JobItem implements Serializable {

 @ManyToOne
 @PrimaryKeyJoinColumn(name = "forumId")
 private Forum forum;

 @ManyToOne
 @PrimaryKeyJoinColumn(name = "parsingJobId")
 private ParsingJob parsingJob;

 @Id
 @Column(name = "forumId", insertable = false, updatable = false)
 private int forumId;

 @Id
 @Column(name = "parsingJobId", insertable = false, updatable = false)
 private int parsingJobId;

 private String server;
 private String comments;

 /**
 * @param forum
 * @param parsingJob
 */
 public JobItem(Forum forum, ParsingJob parsingjob) {
 super();
 setForumId(forum.getId());
 setParsingJobId(parsingjob.getId());

 }

创建实例并保持不变时,出现以下异常。它说该参数的索引超出范围,所以我想它尝试添加6个参数(用于我的6个字段)而不是4个。我是否缺少一些注释?

有任何想法吗 ?

我在JBoss 4.2和MySql上运行

错误消息如下
2007-07-19 17:19:15,968 DEBUG [org.hibernate.SQL] insert into jobitems (server, comments, forumId, parsingJobId) values (?, ?, ?, ?)
2007-07-19 17:19:15,968 INFO [org.hibernate.type.IntegerType] could not bind value '1' to parameter: 5; Parameter index out of range (5 > number of parameters, which is 4).
2007-07-19 17:19:15,968 DEBUG [org.hibernate.jdbc.AbstractBatcher] about to close PreparedStatement (open PreparedStatements: 1, globally: 1)
2007-07-19 17:19:15,968 DEBUG [org.hibernate.jdbc.ConnectionManager] skipping aggressive-release due to flush cycle
2007-07-19 17:19:15,968 DEBUG [org.hibernate.util.JDBCExceptionReporter] could not insert: [com.vico.software.tools.parsing.entities.JobItem] [insert into jobitems (server, comments, forumId, parsingJobId) values (?, ?, ?, ?)]
java.sql.SQLException: Parameter index out of range (5 > number of parameters, which is 4).
 at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:910)
 at com.mysql.jdbc.PreparedStatement.setInternal(PreparedStatement.java:2740)
 at com.mysql.jdbc.PreparedStatement.setInternal(PreparedStatement.java:2771)
 at com.mysql.jdbc.PreparedStatement.setInt(PreparedStatement.java:2722)
 at org.jboss.resource.adapter.jdbc.WrappedPreparedStatement.setInt(WrappedPreparedStatement.java:117)

最佳答案

您正在使用与JPA 1.0兼容的映射,即具有相同列的关系和冗余@Column字段。 @PrimaryKeyJoinColumn类似于@JoinColumn(..., insertable = false, updatable = false),请参阅here。其中之一必须是可写的才能正常工作。两者的映射方式均不可写。

因此,基本上,您可以做两件事:

  • 将只读放入关系
  • 将只读置于冗余@Column的字段


  • ...然后将其从另一个中删除。

    您可以将@PrimaryKeyJoinColumn替换为@JoinColumn,并且应该这样做。但是, Hibernate以冗余@Column字段的只读问题而著称,因此您必须在此处从..., insertable = false, updatable = false)中删除@Column。这就是导致此奇怪异常的原因。我确实认为这是一个错误。这会影响Hibernate 3.x的所有最新版本,包括4.0。

    09-11 17:52
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