java - Spring Data JPA， native 查询，返回错误的字段类型

我的存储库中有以下本机查询方法：

@Query(value="SELECT appSub.ApplicationFormId as appFormId, appSub.profileId as profileId, "
                + "p.CASId as profileCASId, ps.programId as programId FROM [unicas_config].[dbo].ApplicationFormEarlyDecisionConfig appFormED "
                + "INNER JOIN [unicas_ux].[dbo].ApplicationSubmission appSub ON appFormED.ApplicationFormId = appSub.applicationFormId "
                + "INNER JOIN [unicas_ux].[dbo].Profile p ON appSub.profileId = p.id "
                + "INNER JOIN [unicas_ux].[dbo].ProgramSelected ps ON p.id=ps.ProfileId AND appSub.applicationFormId = ps.instanceId "
                + "WHERE appFormED.EarlyDecisionVerdictDate >=:fromDate AND appFormED.EarlyDecisionVerdictDate <:toDate "
                + "AND appSub.EarlyDecisionStatus='Applied Early Decision' "
                + "AND appSub.ApplicationStatus='Received' "
                + "AND ps.IsPaid =1 "
                + "ORDER BY appSub.ApplicationFormId",nativeQuery = true)
List<Object[]> getAllEarlyDecisionApplicantsWithPaidProgramsOnVerdictDate(@Param("fromDate") Date fromDate, @Param("toDate") Date toDate);

现在，我想映射返回的结果：

long appFormId = (Long)obj[0]
long profileId = (Long)obj[1]
long programId = (Long)obj[3]

当我这样做时，我得到了java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.Long，因为Hibernate考虑使用这些Integer类型的id而不是Long。

请告诉我如何以编程方式告诉Hibernate返回正确的类型。

最佳答案

为了安全起见，我总是将数字类型转换为Number，然后从中获取所需类型的值，因为JDBC驱动程序可以根据类型返回Integer，Long，BigDecimal等。数据库列：

((Number) obj[0]).longValue()

当然，如果列可为空，请不要忘记检查null。

关于java - Spring Data JPA， native 查询，返回错误的字段类型，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/42556809/