c++ - 用字符串回显用户输入

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我的程序应该显示所请求形状的名称。我不习惯使用字符串，因此如何回显用户输入（C显示圆锥体等）？我在猜测某种if语句，但不确定如何编写。

样品：

Hello.  Welcome to the shape volume  computing program.
Which shape do  you have?  (C for cone, U for   cube,   Y, for  cylinder P for pyramid, S   for sphere, or Q    to quit)
Enter   shape:  U
okay,   cube.   Please enter the length of a side:  3
okay,   the length of the side = 3
the volume  = 27
enter   shape: C
okay,   cone.   Please enter the radius of the  base:   2
please enter the height:    3
okay,   the radius =  2 and the height  = 3
the volume  = 12.56
enter   shape: Q
bye!

码：

int main()
{
    string C,U,Y,P,S;
    C= "cone";
    U= "cube";
    Y= "cylinder";
    P= "pyramid";
    S= "sphere";
    int Q= -1;

    cout<< " Enter C for cone, U for cube, Y for cylinder, P for pyramid, S for sphere or Q
    to quit. " <<endl;
    cin>> C,U,Y,P,S,Q;

    if(Q= -1)
        cout<< " Goodbye! " <<endl;
    return 0;
}

最佳答案

该声明

cin>> C,U,Y,P,S,Q;

手段

(cin>> C),U,Y,P,S,Q;

因为逗号运算符的优先级最低。

因此，它将一个字符输入到C，然后（这是逗号运算符的作用）对U，Y，P，S和Q求值，后者的值作为表达式结果，然后将其丢弃。

那可能不是您想的那样。

为了使这项工作可以


使用单个输入变量，例如line。
使用getline标头中的<string>函数输入一行。
检查输入的行是"U"，在这种情况下执行U还是在其他情况下执行其他操作。 if语句对此很有用。

关于c++ - 用字符串回显用户输入，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/13079994/