在进行教程工作时,我花了永远的时间来实现小数点,现在我有了一个可以在公式中使用的小数点,但是问题是它反转了输入-例如,输入1.4,计算器屏幕将其显示为4.1-i知道这与我对变量的整理有关。计划使用BOOL而不是float。但是。

编码:

     - (IBAction) pressedDecimal: (id) sender
     {
       pressedDec = 1;
     }

    - (IBAction) pressedDigit: (id) sender
     {
       if (pressedDec == 1)
       {currentNumber = .1 * currentNumber + (double)[sender tag];
       calculatorScreen.text = [NSString stringWithFormat:@"%g",currentNumber];
      }
else

     {

       currentNumber =  currentNumber * 10 + (double)[sender tag];
       calculatorScreen.text = [NSString stringWithFormat:@"%g",currentNumber];
       pressedDec = 0;

      }
     }



  - (IBAction) pressedOperation: (id) sender
   {
if (currentOperation == 0) result = currentNumber;
else {
    switch (currentOperation) {
        case 1:
            result = result + currentNumber;
            break;
        case 2:
            result = result - currentNumber;
            break;
        case 3:
            result = result * currentNumber;
            break;
        case 4:
            result = result / currentNumber;
            break;
        case 5:
            currentOperation = 0;
            break;


    }

}
currentNumber = 0;
calculatorScreen.text = [NSString stringWithFormat:@"%g",result];
if ([sender tag] == 0) result = 0;
currentOperation = [sender tag];
  }

最佳答案

请更仔细地考虑这段从代码中提取的内容:

currentNumber = .1 * currentNumber + (double)[sender tag];


(我不是很明确,因为如果我理解正确的问题,那么您就是为了学习而这样做,并且您必须思考的越多,您就会学得越好:-)。)

09-30 14:44
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