template <typename List>
class list_base {
    typedef typename List::node node;

};


template <typename T, typename Allocator = allocator<T>>
class list: private list_base<list<T, Allocator>> {
    typedef Allocator allocator_type;

    class node {

    };
};

当我实例化list<int> x时,它给了我一个错误:
../src/Console.cpp: In instantiation of ‘class list_base<list<int> >’:
../src/Console.cpp:27:7:   required from ‘class list<int>’
../src/Console.cpp:36:12:   required from here
../src/Console.cpp:21:30: error: no type named ‘node’ in ‘class list<int>’

类型节点已明确定义。这里会发生什么?

最佳答案

题:



当实例化基类时,list尚未完全定义。

关于c++ - 模板类型名实例化错误,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/29271917/

10-12 00:26
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