我有一个bootstrap modal pop up
。里面有很多控件和提交按钮。因此,成功提交后,我想关闭该弹出窗口。下面的代码将消息显示为Record Saved successfully
。
if (strMessage == "Success" && strSaveSubmit == "Draft")
{
ClientScript.RegisterStartupScript(Page.GetType(), "erroralert", "alert('Record Saved as Draft Successfully');", true);
}
但与此同时,我想关闭无法打开的模式弹出窗口。这是那个div
<div class="modals">
<form id="frmFileUpload" runat="server">
<div class="col-sm-6">
<asp:HiddenField ID="hdnFileInfo" runat="server" />
<asp:HiddenField ID="hdnClose" runat="server" />
<label>Sap ID</label>
<asp:Label ID="lblSapId" Text="" runat="server" />
</div>
<div class="col-sm-6">
<label>Candidate ID</label>
<asp:Label ID="lblCandidateId" Text="" runat="server" />
</div>
<div class="col-sm-6">
<label>Technical Feasible</label>
<div class="selectWraper">
<asp:DropDownList ID="ddlTechFeasible" runat="server">
<asp:ListItem Text="Select" Value="Select" />
<asp:ListItem Text="YES" Value="YES" />
<asp:ListItem Text="NO" Value="NO" />
</asp:DropDownList>
</div>
</div>
<div class="col-sm-6">
<div class="upload">
<label>Upload Document</label>
<asp:HiddenField ID="hdnGetFileName" runat="server" />
<div id="dvFileUpload">
<asp:FileUpload runat="server" ID="flufileUpload" AllowMultiple="true" CssClass="chooseFile" />
</div>
</div>
</div>
<div class="col-sm-6">
<label>Remarks</label>
<asp:TextBox ID="txtRemarks" runat="server" TextMode="MultiLine" />
</div>
<div class="col-sm-6" style="overflow: auto; height: 100px;">
<asp:GridView ID="grdFilesInfo" runat="server" AutoGenerateColumns="false" EmptyDataText="No files uploaded">
<Columns>
<asp:BoundField DataField="Text" HeaderText="Uploaded Files" />
<asp:TemplateField>
<ItemTemplate>
<asp:LinkButton ID="lnkDownload" ToolTip="download files" CssClass="fa fa-download" CommandArgument='<%# Eval("Value") %>' runat="server" OnClick="lnkDownload_Click"></asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<asp:LinkButton ID="lnkDelete" ToolTip="delete files" CssClass="fa fa-trash-o" CommandArgument='<%# Eval("Value") %>' runat="server" OnClientClick="if (!confirm('Are you sure you want delete the file?')) return false;" OnClick="lnkDelete_Click" />
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
</div>
<div class="clearfix"></div>
<div class="modalButton">
<asp:Button ID="btnSaveDraft" runat="server" Text="Save as Draft" OnClick="btnSaveDraft_Click" CssClass="button" OnClientClick="return SaveOrDraft('Draft');" />
<asp:Button ID="btnSubmit" runat="server" Text="Submit" data-dismiss="modal" OnClick="btnSubmit_Click" CssClass="button" OnClientClick="return SaveOrDraft('Draft');" />
</div>
</form>
</div>
最佳答案
JQuery和Ajax是您的朋友。
您可以将其添加到文档中。准备好...
$(document).ready(function() {
$('#<%= btnSubmit.ClientID %>').on('click', function () {
$('.modals').hide(); // hides anything with 'modals' as the class
}
}
您也可以给模态一个ID并使用$('#ModalID')。hide();
您可以为提交按钮分配一个静态ID,但是将为您提取ID。
这是ajax操作吗?从那里的代码看来,它将执行回发并重新加载页面。
关于javascript - 在服务器端提交消息后,关闭模式弹出窗口,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/50023063/