php - 如何在网站上的相对时间内获取MySQL表的时间戳

我想一步一步地知道如何将mysql表中的时间戳转换为我网站上的相对时间（4秒前，5个月前…）。
有关信息，我的时间戳列命名为creation，表命名为users。
我试过的密码：

function relativedate($secs) {
    $second = 1;
    $minute = 60;
    $hour = 60*60;
    $day = 60*60*24;
    $week = 60*60*24*7;
    $month = 60*60*24*7*30;
    $year = 60*60*24*7*30*365;

    if ($secs <= 0) { $output = "now";
    }elseif ($secs > $second && $secs < $minute) { $output = round($secs/$second)." second";
    }elseif ($secs >= $minute && $secs < $hour) { $output = round($secs/$minute)." minute";
    }elseif ($secs >= $hour && $secs < $day) { $output = round($secs/$hour)." hour";
    }elseif ($secs >= $day && $secs < $week) { $output = round($secs/$day)." day";
    }elseif ($secs >= $week && $secs < $month) { $output = round($secs/$week)." week";
    }elseif ($secs >= $month && $secs < $year) { $output = round($secs/$month)." month";
    }elseif ($secs >= $year && $secs < $year*10) { $output = round($secs/$year)." year";
    }else{ $output = " more than a decade ago"; }

    if ($output <> "now"){
        $output = (substr($output,0,2)<>"1 ") ? $output."s" : $output;
    }
    return $output;
}



echo relativedate(60); // 1 minute

最佳答案

显示相对时间/日期的用例。
我在这段代码中创建了“sample”表。

SELECT *, CASE
WHEN creation between date_sub(now(), INTERVAL 60 minute) and now() THEN concat(minute(TIMEDIFF(now(), creation)), ' minutes ago')
WHEN datediff(now(), creation) = 1 THEN 'Yesterday'
WHEN creation between date_sub(now(), INTERVAL 24 hour) and now() THEN concat(hour(TIMEDIFF(NOW(), creation)), ' hours ago')
ELSE date_format(creation, '%a, %m/%d/%y')
END as date FROM sample

这将生成一个新列“date”，可用于输出相对时间。

关于php - 如何在网站上的相对时间内获取MySQL表的时间戳，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/17334912/