我有个计划
start-time = 4:15 PM
end-time = 2:00 AM
如果我的
current-time
(假设9:15 pm与开始或结束时间的格式相同)介于start-time
和end-time
之间,则转到screen 1
其他明智的转到screen 2
我的问题是如何比较大于或等于“开始时间”和小于或等于“结束时间”。我试图将给定的时间值转换成
current-time
并进行比较,但milliseconds
似乎大于“结束时间=2:00 am”,因为2:00 am将在午夜之后,这意味着如果“9:15 pm day=thurday,那么2:00 am将是星期五”。我已经找了很多,但找不到。任何形式的帮助都将不胜感激。编辑:
当前时间、开始时间和结束时间所有值都取为
current-time = 9:15 PM
编辑2
代码SPINET:
long currentTime = getMillis("9:15 PM");
long startTime = getMillis("4:15 PM");
long endTime = getMillis("2:00 AM");//this will be the next day's time confusing part for me
if(currentTime >= startTime && currentTime <= endTime)
{
//goto screen 1
}
else
{
// goto screen 2
}
private long getMillis(String givenTime)
{
SimpleDateFormat sdf = new SimpleDateFormat("h:mm a");
try {
Date mDate = sdf.parse(givenTime);
long timeInMilliseconds = mDate.getTime();
System.out.println("Date in milli :: " + timeInMilliseconds);
return timeInMilliseconds;
} catch (ParseException e) {
e.printStackTrace();
}
return 0;
}
最佳答案
步骤1:
你只需要在结束时间比开始时间短的时候增加一天。
步骤2:
应用条件检查当前时间是否介于开始时间和结束时间之间
try {
Date mToday = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("hh:mm aa");
String curTime = sdf.format(mToday);
Date start = sdf.parse("4:15 PM");
Date end = sdf.parse("2:00 AM");
Date userDate = sdf.parse(curTime);
if(end.before(start))
{
Calendar mCal = Calendar.getInstance();
mCal.setTime(end);
mCal.add(Calendar.DAY_OF_YEAR, 1);
end.setTime(mCal.getTimeInMillis());
}
Log.d("curTime", userDate.toString());
Log.d("start", start.toString());
Log.d("end", end.toString());
if (userDate.after(start) && userDate.before(end)) {
Log.d("result", "falls between start and end , go to screen 1 ");
}
else{
Log.d("result", "does not fall between start and end , go to screen 2 ");
}
} catch (ParseException e) {
// Invalid date was entered
}