#include<stdio.h>
int main(void) {
int m=2, a=5, b=4;
float c=3.0, d=4.0;
printf("%.2f,%.2f\n", (a/b)*m, (a/d)*m);
printf("%.2f,%.2f\n", (a/d)*m, (a/b)*m);
return 0;
}
结果是:
2.50,0.00
2.50,-5487459522906928958771870404376799406808566324353377030104786519743796498661129086808599726405487030183023928761546165866809436788166721199470577627133198744209879004896284033606071946689658593354711574682628407789000148729336462084532657713450945423953627239707603534923756075420253339949731915621203968.00
我想知道是什么导致了这种差异。
但是,如果我将int改为float,答案与我预期的一样。
结果是:
2.50,2.50
2.50,2.50
最佳答案
您使用了错误的格式说明符,请尝试以下操作:
#include<stdio.h>
int main(void)
{
int m=2,a=5,b=4;
float fm=2,fa=5,fb=4;
float c=3.0,d=4.0;
//First expression in this printf is int and second is float due to d
printf("%d , %.2f\n\n",(a/b)*m,(a/d)*m);
//Second expression in this printf is int and first is float due to d
printf("%.2f , %d\n\n",(a/d)*m,(a/b)*m);
printf("%.2f , %.2f\n\n",(fa/b)*fm,(fa/d)*fm);
printf("%.2f , %.2f\n\n",(fa/d)*fm,(fa/b)*fm);
return 0;
}
输出:
2 , 0
0 , 1074003968
2.50 , 2.50
2.50 , 2.50
C99标准第7.19.6.1 p9节规定:
如果任何参数不是相应转换规范的正确类型,则行为未定义。