试图制作我的第一个程序“ A Basic Mind Game”。
每次我尝试运行它时，都不会显示任何内容，也不知道出了什么问题。
希望您能给我一些帮助或建议。
顺便说一句，我在Java编程领域几乎是一个NOOB，所以请放轻松一点：)
这是代码：
import java.util.*;
import java.util.Scanner.*;
import java.util.ArrayList.*;
public class Main {
public static void start() {
int answer = (int) (Math.random() * 1000 + 1) ;
int tries = 0 ;
int player ;
String name = "name" ;
String quit = "quit";
String y = "yes";
String n = "no";
String guess = ("player") ;
String another = ("Y") ;
Scanner input = new Scanner (System.in);
System.out.println( " Welcome to Guessing Game " ) ;
System.out.print("Please enter a number between 1 and 1000 : ");
player = input.nextInt();
long startTime = System.currentTimeMillis();
int currentGuess = -1;
while(another.equalsIgnoreCase("y")) {
do
{
if (guess.equalsIgnoreCase(quit))
{
System.out.println("Leaving Us So Soon?");
System.exit(0);
}
try {
currentGuess = Integer.parseInt(guess);
} catch (NumberFormatException nfe)
{
System.out.println("Stupid Guess I Wont Count That.");
player = input.nextInt();
tries++;
}
if (currentGuess < answer )
{
System.out.println("too low");
player = input.nextInt();
tries++;
}
else if(currentGuess > answer )
{
System.out.println("too high");
player = input.nextInt();
tries++;
}
//if the guess is invalid
if (currentGuess < 0 || currentGuess > 1000)
{
System.out.println("Stupid Guess I Wont Count That.");
player = input.nextInt();
tries++;
}
else if (currentGuess == answer)
{
//stop stop watch
long endTime = System.currentTimeMillis();
//calculate game time
long gameTime = endTime - startTime;
System.out.println("You Rock Dude, Good Job!");
System.out.println("You guessed " + tries + " times in " + (int)(gameTime/1000) + " seconds.");
System.out.println("Please enter your name.");
name = input.nextLine();
}
} while (player != answer);
Scanner playGame = new Scanner(System.in);
System.out.print("Want to go again?(y/n).....");
another = playGame.nextLine();
}
}
public static void main(String[] args) {
}
}
最佳答案
您的主要方法是空的。
main方法包含将在应用程序启动时运行的代码。如果main方法为空，则在运行应用程序时不会发生任何事情。