我只想检查该链接是否为Google Maps链接

例如:

var urls =[
    /// correct urls
    "https://www.google.com/maps",
    "https://www.google.fr/maps",
    "https://google.fr/maps",
    "http://google.fr/maps",
    "https://www.google.de/maps",
    "https://www.google.com/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4",
    "https://www.google.de/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4",
    "https://www.google.com/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4&layer=t&lci=com.panoramio.all,com.google.webcams,weather",
    "https://www.google.com/maps?ll=37.370157,0.615234&spn=45.047033,93.076172&t=m&z=4&layer=t",

    "https://www.google.com/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4",
    "https://www.google.de/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4",
    "https://www.google.com/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4&layer=t&lci=com.panoramio.all,com.google.webcams,weather",
    "https://www.google.com/maps?ll=37.370157,0.615234&spn=45.047033,93.076172&t=m&z=4&layer=t",

    /// error urls
    "https://www.google.com/",
    "https://zzz.google.com/maps",
    "https://www.google.com/+",
    "httpsxyz://www.google.com/maps",
    "http://www.anotherdomain.com/+"
    ];

我对Regex感到很糟糕,并尝试使用JavaScript Regex Generator,但对我来说仍然很难。

我只有..
Reg = /^http\:\/\/|https\:\/\/|www\.google$/;

和它的失败! :(

但是我为大家做了现场测试:http://jsbin.com/onuyux/1/edit?javascript,live

编辑:2

在我从@joel harkes@dan1111获得帮助之后,我得到了正则表达式
/^https?\:\/\/(www\.)?google\.[a-z]+\/maps\b/

这是仅用于google.{TLD}/maps的正则表达式,那么maps.google。{TLD}呢?

我只想通过这种方式验证Google Maps网址和网址(看图片)

(如果可能),我想验证是否设置了地址或经纬度(使用liq参数检查?)(例如,不仅是“maps.google.com”。)

更新列表+代码:
/// correct urls
"https://www.google.com/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4",
"https://www.google.de/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4",
"https://www.google.com/maps?ll=37.0625,-95.677068&spn=45.197878,93.076172&t=h&z=4&layer=t&lci=com.panoramio.all,com.google.webcams,weather",
"https://www.google.com/maps?ll=37.370157,0.615234&spn=45.047033,93.076172&t=m&z=4&layer=t",
"https://maps.google.com/maps?q=New+York,+NY,+USA&hl=no&sll=19.808054,-63.720703&sspn=54.337928,93.076172&oq=n&hnear=New+York&t=m&z=10",
"https://www.google.com/maps?q=New+York,+New+York,+USA&hl=no&ll=40.683762,-73.925629&spn=0.708146,1.454315&sll=41.47566,-72.026367&sspn=11.190693,23.269043&oq=new&hnear=New+York&t=m&z=10",

/// error urls
"https://www.google.com/",
"https://zzz.google.com/maps",
"https://www.google.com/+",
"httpsxyz://www.google.com/maps",
"http://www.anotherdomain.com/+",
"http://maps.google.com/",
"http://google.com/maps",
"http://google.de/maps",
"?q=New+York,+New+York,+USA&hl=no&ll=40.683762,-73.925629&spn=0.708146,1.454315&sll=41.47566,-72.026367&sspn=11.190693,23.269043&oq=new&hnear=New+York&t=m&z=10",
"&sll=41.47566,-72.026367&sspn=11.190693,23.269043&oq=new&hnear=New+York&t=m&z=10"

在线测试: http://jsbin.com/onuyux/25/edit?javascript,live

最佳答案

完成 dan1111 的答案,这是一种与指定域匹配并检查ll GET变量是否设置的模式:

Reg = /^https?\:\/\/(www\.)?google\.[a-z]+\/maps\/?\?([^&]+&)*(ll=-?[0-9]{1,2}\.[0-9]+,-?[0-9]{1,2}\.[0-9]+|q=[^&+])+($|&)/;

我无法对其进行测试(jsbin已关闭),但它应与包含ll或q参数中至少一个的任何URL匹配。

编辑:

我添加了 map 。子域并修复了一个小的错字。在q=之后,+应该在字符类之外,以使其重复:q=[^&]+而不是q=[^&+]
话虽如此,这是您的正则表达式:
Reg = /^https?\:\/\/(www\.|maps\.)?google\.[a-z]+\/maps\/?\?([^&]+&)*(ll=-?[0-9]{1,2}\.[0-9]+,-?[0-9]{1,2}\.[0-9]+|q=[^&]+)+($|&)/;

EDIT2 :

要接受google.co.uk样式域,请使用以下正则表达式。
Reg = /^https?\:\/\/(www\.|maps\.)?google(\.[a-z]+){1,2}\/maps\/?\?([^&]+&)*(ll=-?[0-9]{1,2}\.[0-9]+,-?[0-9]{1,2}\.[0-9]+|q=[^&]+)+($|&)/;

希望它现在能覆盖所有URL。

10-05 20:42
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