我正在寻找有关如何保护我的剩余根资源的一些建议

@Path("/employee")
public class EmployeeResource {

    @GET
    @Produces("text/html")
    public String get(
        @QueryParam("name") String empname,
        @QueryParam("sn") String sn) {

         // Return a data back.
    }
}

我已经阅读了有关基本认证和OAuth的文章,我知道这个概念,但是我正在寻找有关如何在代码中实现它的方法。

谢谢

最佳答案

声明一个拦截器:

 <bean id="securityInterceptor" class="AuthenticatorInterceptor">
<property name="users">
  <map>
<entry key="someuser" value="somepassword"/>
  </map>
</property>

然后使用它:
  <jaxrs:server address="/">
      <jaxrs:inInterceptors>
          <ref bean="securityInterceptor"/>
      </jaxrs:inInterceptors>
      (etc)

然后是您的AuthenticationInterceptor,大致如下:
import java.util.Map;

import org.apache.cxf.message.Message;
import org.apache.cxf.phase.PhaseInterceptor;
import org.apache.cxf.phase.AbstractPhaseInterceptor;
import org.apache.cxf.phase.Phase;
import org.apache.cxf.configuration.security.AuthorizationPolicy;
import org.apache.cxf.interceptor.Interceptor;

import org.springframework.beans.factory.annotation.Required;

public class AuthenticatorInterceptor extends AbstractPhaseInterceptor<Message> {

    private Map<String,String> users;

    @Required
    public void setUsers(Map<String, String> users) {
        this.users = users;
    }

    public AuthenticatorInterceptor() {
        super(Phase.RECEIVE);
    }

    public void handleMessage(Message message) {

        AuthorizationPolicy policy = message.get(AuthorizationPolicy.class);

    if (policy == null) {
        System.out.println("User attempted to log in with no credentials");
        throw new RuntimeException("Denied");
        }

    String expectedPassword = users.get(policy.getUserName());
    if (expectedPassword == null || !expectedPassword.equals(policy.getPassword())) {
        throw new RuntimeException("Denied");
    }
    }

}

读者可以以更方便的方式定义可接受的凭据。

关于rest - 如何使用JAX-RS进行身份验证,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/4124831/

10-09 06:15
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