编辑:我正在尝试获得彩色的单行,而不是整个网格
因此,我要尝试的是单击画布时,选定的线会移动并变为彩色。
我已经移动了线路,但不能get them colored。我知道我必须使用strokeStyle
属性,但是如何使特定的行变成彩色?
我尝试将strokeStyle
放在draw_each
方法下,但这不起作用,我也不知道为什么。这是我的代码:
//draw each line in array
function draw_each(p1, p2, p3, p4) {
$.moveTo(p1.x, p1.y);
$.lineTo(p2.x, p2.y);
$.moveTo(p1.x, p1.y);
$.lineTo(p4.x, p4.y);
if (p1.ind_x == gnum - 2) {
$.moveTo(p3.x, p3.y);
$.lineTo(p4.x, p4.y);
}
if (p1.ind_y == gnum - 2) {
$.moveTo(p3.x, p3.y);
$.lineTo(p2.x, p2.y);
}
}
https://codepen.io/diazabdulm/pen/qJyrZP?editors=0010
最佳答案
在我看来,您想要的实际上是根据所施加的力为每个线段生成颜色,从而使波浪效果保持其效果。
您可以做的是将每个节点在两个轴上的速度的中值保存为平均值,以表示它们当前承受的力,并在图形部分中获取组成网格的每个线段的所有节点的中值并由此构成一种颜色。
但这有一个缺点:您的代码编写得足够好,可以将整个网格组成单个子路径,从而限制了所需的图形数量。但是现在,我们必须使每个段都有自己的子路径(因为它们将具有自己的颜色),因此我们将在性能方面放宽很多...
var gnum = 90; //num grids / frame
var _x = 2265; //x width (canvas width)
var _y = 1465; //y height (canvas height)
var w = _x / gnum; //grid sq width
var h = _y / gnum; //grid sq height
var $; //context
var parts; //particles
var frm = 0; //value from
var P1 = 0.0005; //point one
var P2 = 0.01; //point two
var n = 0.98; //n value for later
var n_vel = 0.03; //velocity
var ŭ = 0; //color update
var msX = 0; //mouse x
var msY = 0; //mouse y
var msdn = false; //mouse down flag
var Part = function() {
this.x = 0; //x pos
this.y = 0; //y pos
this.vx = 0; //velocity x
this.vy = 0; //velocity y
this.ind_x = 0; //index x
this.ind_y = 0; //index y
};
Part.prototype.frame = function() {
if (this.ind_x == 0 || this.ind_x == gnum - 1 || this.ind_y == 0 || this.ind_y == gnum - 1) {
return;
}
var ax = 0; //angle x
var ay = 0; //angle y
//off_dx, off_dy = offset distance x, y
var off_dx = this.ind_x * w - this.x;
var off_dy = this.ind_y * h - this.y;
ax = P1 * off_dx;
ay = P1 * off_dy;
ax -= P2 * (this.x - parts[this.ind_x - 1][this.ind_y].x);
ay -= P2 * (this.y - parts[this.ind_x - 1][this.ind_y].y);
ax -= P2 * (this.x - parts[this.ind_x + 1][this.ind_y].x);
ay -= P2 * (this.y - parts[this.ind_x + 1][this.ind_y].y);
ax -= P2 * (this.x - parts[this.ind_x][this.ind_y - 1].x);
ay -= P2 * (this.y - parts[this.ind_x][this.ind_y - 1].y);
ax -= P2 * (this.x - parts[this.ind_x][this.ind_y + 1].x);
ay -= P2 * (this.y - parts[this.ind_x][this.ind_y + 1].y);
this.vx += (ax - this.vx * n_vel);
this.vy += (ay - this.vy * n_vel);
//EDIT\\
// store the current velocity (here base on 100 since it will be used with hsl())
this.color = (Math.abs(this.vx)+Math.abs(this.vy)) * 50;
this.x += this.vx * n;
this.y += this.vy * n;
if (msdn) {
var dx = this.x - msX;
var dy = this.y - msY;
var ɋ = Math.sqrt(dx * dx + dy * dy);
if (ɋ > 50) {
ɋ = ɋ < 10 ? 10 : ɋ;
this.x -= dx / ɋ * 5;
this.y -= dy / ɋ * 5;
}
}
};
function go() {
parts = []; //particle array
for (var i = 0; i < gnum; i++) {
parts.push([]);
for (var j = 0; j < gnum; j++) {
var p = new Part();
p.ind_x = i;
p.ind_y = j;
p.x = i * w;
p.y = j * h;
parts[i][j] = p;
}
}
}
//move particles function
function mv_part() {
for (var i = 0; i < gnum; i++) {
for (var j = 0; j < gnum; j++) {
var p = parts[i][j];
p.frame();
}
}
}
//draw grid function
function draw() {
//EDIT
// we unfortunately have to break the drawing part
// since each segment has its own color, we can't have a single sub-path anymore...
ŭ -= .5;
for (var i = 0; i < gnum - 1; i += 1) {
for (var j = 0; j < gnum - 1; j += 1) {
var p1 = parts[i][j];
var p2 = parts[i][j + 1];
var p3 = parts[i + 1][j + 1];
var p4 = parts[i + 1][j];
draw_each(p1, p2, p3, p4);
}
}
}
//draw each in array
function draw_each(p1, p2, p3, p4) {
// for each segment we set the color
$.strokeStyle = `hsl(0deg, ${(p1.color+p2.color+p3.color+p4.color) / 4}%, 50%)`;
// begin a new sub-path
$.beginPath();
$.moveTo(p1.x, p1.y);
$.lineTo(p2.x, p2.y);
$.moveTo(p1.x, p1.y);
$.lineTo(p4.x, p4.y);
if (p1.ind_x == gnum - 2) {
$.moveTo(p3.x, p3.y);
$.lineTo(p4.x, p4.y);
}
if (p1.ind_y == gnum - 2) {
$.moveTo(p3.x, p3.y);
$.lineTo(p2.x, p2.y);
}
// and stroke it
$.stroke();
}
//call functions to run
function calls() {
$.fillStyle = "hsla(0, 0%, 7%, 1)";
$.fillRect(0, 0, _x, _y);
mv_part();
draw();
frm++;
}
var c = document.getElementById('canv');
var $ = c.getContext('2d');
$.fillStyle = "hsla(0, 0%, 7%, 1)";
$.fillRect(0, 0, _x, _y);
function resize() {
if (c.width < window.innerWidth) {
c.width = window.innerWidth;
}
if (c.height < window.innerHeight) {
c.height = window.innerHeight;
}
}
requestAnimationFrame(go);
document.addEventListener('click', MSMV, false);
document.addEventListener('click', MSDN, false);
function MSDN(e) {
msdn = true;
window.setTimeout(function() {
msdn = false;
}, 100);
}
function MSUP(e) {
msdn = false;
}
function MSMV(e) {
var rect = e.target.getBoundingClientRect();
msX = e.clientX - rect.left;
msY = e.clientY - rect.top;
}
window.onload = function() {
run();
function run() {
requestAnimationFrame(calls);
requestAnimationFrame(run);
}
resize();
};
onresize = resize;
body {
width: 100%;
overflow: hidden;
cursor:move;
}
<canvas id="canv" width="150" height="150"></canvas>
现在,一种性能更高但外观不太好的方法是在发生点击的位置绘制一个径向渐变,并进行一些合成,您将能够获得便宜的产品,但可能会有所帮助。实际上需要大量编码才能同时获得多个这样的渐变...