java - Java，删除文本并在stringBuffer中换行

我将这段文本输入到字符串缓冲区中，

857,9/25/14
REEL SCAN,BASIS WT
,0.7600,66067.3,50212.4,61.0
,49.572,-0.3720,0.0000
,111.89,108.28,94.72,106.23
,99.82,83.41

运行此后

StringBuffer stringBuffer = new StringBuffer();
                String line;
                while ((line = bufferedReader.readLine()) != null) {

                    line = line.replace("REEL SCAN" + "," + "BASIS WT", "");
                    stringBuffer.append(line.trim());
                    stringBuffer.append("\n");
                }

我明白了

857,9/25/14

,0.7600,66067.3,50212.4,61.0
,49.572,-0.3720,0.0000
,111.89,108.28,94.72,106.23
,99.82,83.41

我如何在同一时间摆脱空白行

857,9/25/14
,0.7600,66067.3,50212.4,61.0
,49.572,-0.3720,0.0000
,111.89,108.28,94.72,106.23
,99.82,83.41

我努力了

line = line.replace("REEL SCAN" + "," + "BASIS WT" + "\n\n", "");

和我在这里发现的其他变化，但没有运气。
我需要的是第二行完全消失了，但是它永远不会是第二行。

最佳答案

也许只是从StringBuffer完全跳过该行

while ((line = bufferedReader.readLine()) != null) {
    if(line.contains("REEL SCAN,BASIS WT") {
        continue;
    }
    stringBuffer.append(line.trim());
    stringBuffer.append("\n");
}

关于java - Java，删除文本并在stringBuffer中换行，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/27366285/