这是数据框。我想要这里的日期为'%Y-%m-%d %H:%M:%S'
格式。
import pandas as pd
df2 = pd.DataFrame([['2017-18','','','','','','','','','','','',''], ['COMPANIES', '01-APR-2017', '01-MAY-2017', '01-JUN-2017',
'01-JULY-2017', '01-AUG-2017', '01-SEP-2017', '01-OCT-2017', '01-NOV-2017', '01-DEC-2017', '01-JAN-2018', '01-FEB-2018', '01-MAR-2018']])
我试过了,
df2.iloc[1, 1:] = df2.iloc[1, 1:].str.replace("JULY", "JUL")
df2.iloc[1, 1:] = df2.iloc[1, 1:].apply(pd.to_datetime, format = '%d-%b-%Y')
但是,它给出了:
0 1 2 3 \
0 2017-18
1 COMPANIES 1491004800000000000 1493596800000000000 1496275200000000000
4 5 6 \
0
1 1498867200000000000 1501545600000000000 1504224000000000000
7 8 9 \
0
1 1506816000000000000 1509494400000000000 1512086400000000000
10 11 12
0
1 1514764800000000000 1517443200000000000 1519862400000000000
我想念什么吗?还有其他方法可以按要求的格式显示日期吗?
我什至尝试:
for i in df2.iloc[1, 1:]:
i = datetime.datetime.fromtimestamp(int(i)).strftime('%Y-%m-%d %H:%M:%S')
但给出一个
ValueError: timestamp out of range for platform localtime()/gmtime() function
最佳答案
您可以使用strftime
访问.dt
例如:
import pandas as pd
df2 = pd.DataFrame([['2017-18','','','','','','','','','','','',''], ['COMPANIES', '01-APR-2017', '01-MAY-2017', '01-JUN-2017',
'01-JULY-2017', '01-AUG-2017', '01-SEP-2017', '01-OCT-2017', '01-NOV-2017', '01-DEC-2017', '01-JAN-2018', '01-FEB-2018', '01-MAR-2018']])
df2.iloc[1, 1:] = df2.iloc[1, 1:].str.replace("JULY", "JUL")
df2.iloc[1, 1:] = df2.iloc[1, 1:].apply(pd.to_datetime, format = '%d-%b-%Y').dt.strftime('%Y-%m-%d %H:%M:%S')
print(df2)
输出:
0 1 2 3 \
0 2017-18
1 COMPANIES 2017-04-01 00:00:00 2017-05-01 00:00:00 2017-06-01 00:00:00
4 5 6 \
0
1 2017-07-01 00:00:00 2017-08-01 00:00:00 2017-09-01 00:00:00
7 8 9 \
0
1 2017-10-01 00:00:00 2017-11-01 00:00:00 2017-12-01 00:00:00
10 11 12
0
1 2018-01-01 00:00:00 2018-02-01 00:00:00 2018-03-01 00:00:00
关于python - 在 Pandas 数据框中将日期转换为日期时间格式时出现问题,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/50347089/