我想比较我的申请中的两个日期
第一个日期是今天的日期
第二个将来自数据库
为了保存第二个日期,我的代码如下: (使用明天的日期来保持简单)
Calendar calendar = Calendar.getInstance();
calendar.add(Calendar.DAY_OF_YEAR, 1);
Date tomorrow = calendar.getTime();
DateFormat dateFormat = new SimpleDateFormat("dd-MMM-yyyy");
String tomorrowAsString = dateFormat.format(tomorrow);
所以
tomorrowAsString (10-Oct-2015)
存储在我数据库的一个表中我以另一种形式检索该日期并将其放入字符串中
String steepingDate = (c.getString(3));
我想我需要将该字符串转换为日期格式,然后使用以下命令获取今天的日期;
Calendar calendar = Calendar.getInstance();
Date today = calendar.getTime();
DateFormat dateFormat = new SimpleDateFormat("dd-MMM-yyyy");
String todayAsString = dateFormat.format(today);
这是我卡住的地方,因为我不确定如何将
steepingDate
转换为Date
,然后比较字符串的实际方法是什么,我尝试了在线查找,但是我有很多不同的方法尝试过,到目前为止都没有奏效。我想知道两者中哪一个是刨丝器编辑:
我结合了一些答案,并提出以下建议;
do {
String steepingDate = (c.getString(3));
SimpleDateFormat formatter = new SimpleDateFormat("dd-MMM-yyyy");
Date steepingdate = formatter.parse(steepingDate);
Calendar calendar = Calendar.getInstance();
Date today = calendar.getTime();
if(today.compareTo(steepingdate)>0)
{
CompleteSteeping.add(c.getString(1));
}
i += 1;
}while (c.moveToNext());
但是
SimpleDateFormat formatter = new SimpleDateFormat("dd-MMM-yyyy");
Date steepingdate = formatter.parse(steepingDate);
我收到一条错误消息:
'不可解析的日期:“java.util.GregorianCalender [time = 1444461352665,areFieldsSet = true,Ienient = true\zone = GMT,firstDayOfWeek = 1,minimalDaysInFirstWeek = 1,ERA = 1,YEAR = 2015,MONTH = 9,WEEK_OF_YEAR = 41 ,WEEK_OF_MONTH = 2,DAY_OF_MONTH = 10,DAY_OF_YEAR = 283,DAY_OF_WEEK = 7,DAY_OF_WEEK_IN_MONTH = 2,AM_PM = 0,HOUR = 7,HOUR_OF_DAY = 7,MINUTE = 15,SECOND = 52,MILLISECOND = 665,ZONE_OFFSET = 0 ]”(偏移量为0)
最佳答案
如果您只想比较字符串,则如下所示:
Calendar calendar = Calendar.getInstance();
calendar.add(Calendar.DAY_OF_YEAR, 1);
Date tomorrow = calendar.getTime();
DateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy");
String tomorrowAsString = dateFormat.format(tomorrow);
calendar = Calendar.getInstance();
Date today = calendar.getTime();
String todayAsString = dateFormat.format(today);
if(tomorrowAsString.equals(todayAsString))
System.out.println(true);
else
System.out.println(false);