在我的应用程序中,我正在从服务器检索记录。记录在xml文件中。我可以把文件放下来并解析它,没有任何麻烦。我将结果存储在HashMap中,并且希望能够将这些结果放入应用程序的SQLite数据库中。
这是HashMap的代码
ArrayList<HashMap<String, String>> StudentDownloads = new ArrayList<HashMap<String, String>>();
String xml = XMLfunctions.getXML(target);
Document doc = XMLfunctions.XMLfromString(xml);
if(XMLfunctions.XMLfromString(xml)==null){
Toast.makeText(this, "Badly Formed File", Toast.LENGTH_LONG).show();
finish();
}
int numResults = XMLfunctions.numResults(doc);
if((numResults <= 0)){
Toast.makeText(this, "There Were No Student Results To Show", Toast.LENGTH_LONG).show();
finish();
}
NodeList nodes = doc.getElementsByTagName("Students");
for (int i = 0; i < nodes.getLength(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element)nodes.item(i);
map.put("Student Id", "Student Id " + XMLfunctions.getValue(e, "StudentId"));
map.put("Student Type", "Student Type" + XMLfunctions.getValue(e, "StudentType"));
map.put("Student Location", "Student Location" + XMLfunctions.getValue(e, "StudentLocation"));
map.put("Student Mother", "Student Mother" + XMLfunctions.getValue(e, "StudentMother"));
StudentDownloads.add(map);}
};
现在在我的应用程序中,我已经创建了一个数据输入表单,该表单使用名为StudentRecord的类,在我的输入表单中,我使用此函数来更新文件
private void addStudent(StudentRecord newRecord){
mDB.beginTransaction();
try {
ContentValues StudentRecordToAdd = new ContentValues();
StudentRecordToAdd.put(Students.STUDENT_ID, newRecord.getStudentName());
StudentRecordToAdd.put(Student.STUDENT_TYPE, newRecord.getStudentType());
StudentRecordToAdd.put(Student.STUDENT_LOCATION, newRecord.getStudentLocation());
StudentRecordToAdd.put(Student.STUDENT_MOTHER, newRecord.getStudentMother());
mDB.insert(Student.STUDENT_TABLE_NAME,Student.STUDENT_ANIMALID, StudentRecordToAdd);
mDB.setTransactionSuccessful();
Toast.makeText(this,"Recorded Added ",0).show();
} finally {
mDB.endTransaction();
}
从HashMap将值获取到NewRecord函数的最佳方法是什么?我看了这么久,我想我已经死了。
谢谢
最佳答案
如果我没看错,听起来您需要将addStudent函数从它现在所在的窗体/活动中移到某种“帮助”类中:
private class dbHelper {
Database mDB; // set this up however you are doing it already
private void addStudent(StudentRecord newRecord){
mDB.beginTransaction();
try {
ContentValues StudentRecordToAdd = new ContentValues();
StudentRecordToAdd.put(Students.STUDENT_ID, newRecord.getStudentName());
StudentRecordToAdd.put(Student.STUDENT_TYPE, newRecord.getStudentType());
StudentRecordToAdd.put(Student.STUDENT_LOCATION, newRecord.getStudentLocation());
StudentRecordToAdd.put(Student.STUDENT_MOTHER, newRecord.getStudentMother());
mDB.insert(Student.STUDENT_TABLE_NAME,Student.STUDENT_ANIMALID, StudentRecordToAdd);
mDB.setTransactionSuccessful();
Toast.makeText(this,"Recorded Added ",0).show();
} finally {
mDB.endTransaction();
}
}
}
然后,在解析XML时只需调用该助手即可
ArrayList<StudentRecord> StudentDownloads = new ArrayList<StudentRecord>();
for (int i = 0; i < nodes.getLength(); i++) {
Element e = (Element)nodes.item(i);
int id = Integer.valueOf(XMLfunctions.getValue(e, "StudentId")));
int type = Integer.valueOf(XMLfunctions.getValue(e, "StudentType")));
String location = XMLfunctions.getValue(e, "StudentLocation"));
String mother = XMLfunctions.getValue(e, "StudentMother"));
StudentRecord newRecord = new StudentRecord(id, type, location, mother);
StudentDownloads.add(newRecord);
}
然后,当您完成处理后:
for (StudentRecord s : StudentDownloads) {
mDBHelper.addStudent(s);
}